所以我正在寻找的是特定日期的标准倒计时。
pitchText = (TextView) findViewById(R.id.pitchText);
pitchText = (TextView) findViewById(R.id.noteText);
这就是我所拥有的，如果我$thepostid = get_the_ID();
$sale_price_dates_to = ( $date = get_post_meta( $thepostid, '_sale_price_dates_to', true ) ) ? date_i18n( 'd-m-Y', $date ) : '';
?>
<p class="price"><?php echo $product->get_price_html(); ?></p>
<p>DATUM: <?php echo $sale_price_dates_to; ?> </p>
<p id="demo"></p>
<script>
// Set the date we're counting down to
var countDownDate = new Date("Sep 5, 2018").getTime();
// Update the count down every 1 second
var x = setInterval(function() {
// Get todays date and time
var now = new Date().getTime();
// Find the distance between now an the count down date
var distance = countDownDate - now;
// Time calculations for days, hours, minutes and seconds
var days = Math.floor(distance / (1000 * 60 * 60 * 24));
var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
var seconds = Math.floor((distance % (1000 * 60)) / 1000);
// Display the result in the element with id="demo"
document.getElementById("demo").innerHTML = days + "d " + hours + "h "
+ minutes + "m " + seconds + "s ";
// If the count down is finished, write some text
if (distance < 0) {
clearInterval(x);
document.getElementById("demo").innerHTML = "EXPIRED";
}
}, 1000);
</script>
，则显示一个奇怪的长号。
所以我想尝试的是echo $date进入
$date现在我只说，var countDownDate = new Date("Sep 5, 2018").getTime();
的倒计时，但我想将sep 5 2018插入其中。
我的$date回复$date，就像那样，我怎么能把它分成几个月和几年呢？