我正在尝试检查对API的调用是否已超时。我尝试在给定的网址中添加额外的端口,例如:google.com:81。
我也尝试使用if(curl_errno($ curl)),但似乎并非如此。
如何实现这样的目标?
$Voornamen = array( '0300013' => "Laurence" , '0266931' => "Peter" , '0267730' => "Pim" , '0279410' => "Arben" , '0297652' => "Robbin" , '0300838' => "Damian");
$Achternamen = array( '0300013' => "Van der Wel" , '0266931' => "Kuipers" , '0267730' => "Hoomans" , '0279410' => "Hajrizaj" , '0297652' => "Visser" , '0300838' => "Trojak");
$Woonplaatsen = array( '0300013' => "Enschede" , '0266931' => "Enschede" , '0267730' => "Enschede" , '0279410' => "Enschede" , '0297652' => "Overdinkel" , '0300838' => "Enschede");
$Leeftijden = array( '0300013' => "17" , '0266931' => "20" , '0267730' => "20" , '0279410' => "19" , '0297652' => "16" , '0300838' => "16");
//$persoon = array_rand($voornaam, 1);
$arr = array($Voornamen,$Achternamen,$Woonplaatsen,$Leeftijden);
multi_array($arr);
function multi_array($array){
foreach ($array as $key => $val){
foreach($val as $v) {
echo "<table>
<tr>
<td>
$v
</td>
</tr>
</table>";
}
}
}
感谢任何帮助!
答案 0 :(得分:0)
你可以找到一个cURL错误列表here,你所追求的错误是public static void main(String args[]){
int first = 1;
int second = 3;
int third = 5;
int n = 5;
int sum = 0;
for(int i=0;i<n;i++){
sum+=first*second*third;
first++;
second+=2;
third+=3;
}
}
PHP有一个名为curl_errno(resource $ch)
的方法,您可以使用它来获取错误号。了解这两个方面,您可以执行以下操作:
CURLE_OPERATION_TIMEDOUT (28)
如果仍然无效,那么您可能需要查看curl_error(resource $ch)
获得的实际卷曲错误,并提供更多信息以便我们提供帮助。