我有一个查询,它按付款方式返回一个总和组
select
RTRIM(shopNo) as Shop_Number,
REPLACE(CONVERT(VARCHAR(10), DateTransaction, 103), '/', '') AS Todays_Date,
CodeModeDePaiement as Mode_Of_Payment,
SUM(convert(DOUBLE PRECISION, Amount * 100 ) * 10) As Amount
from InvoiceSettlement
where CodeModeDePaiement in
(101,130,132,135,104,103,124,107,
136,117,131,410,106,122,109,102,105,112,133,999)
and DateTransaction = '2017/12/31'
group by ShopNo,DateTransaction,CodeModeDePaiement
输出结果如下:
Shop_Number Todays_Date Mode_Of_Payment Amount
2 31122017 102 18421610
2 31122017 130 2332371390
2 31122017 132 1082810
2 31122017 106 66457640
2 31122017 117 23925000
2 31122017 133 5700000
2 31122017 999 -490653940
2 31122017 101 2404194870
我希望结果始终显示Mode_of_Payment(101 + 999)的总金额为101.我需要如下结果:
Shop_Number Todays_Date Mode_Of_Payment Amount
2 31122017 102 18421610
2 31122017 130 2332371390
2 31122017 132 1082810
2 31122017 106 66457640
2 31122017 117 23925000
2 31122017 133 5700000
2 31122017 101 1913540930
答案 0 :(得分:2)
使用CASE
表达式将101和999映射到同一个东西:
SELECT
RTRIM(shopNo) AS Shop_Number,
REPLACE(CONVERT(VARCHAR(10), DateTransaction, 103), '/', '') AS Todays_Date,
CASE WHEN CodeModeDePaiement IN (101, 999)
THEN 101
ELSE CodeModeDePaiement END as Mode_Of_Payment,
SUM(CONVERT(DOUBLE PRECISION, Amount * 100 ) * 10) AS Amount
FROM InvoiceSettlement
WHERE CodeModeDePaiement IN (101, 130, 132, 135, 104, 103, 124, 107, 136, 117,
131, 410, 106, 122, 109, 102, 105, 112, 133, 999) AND
DateTransaction = '2017/12/31'
GROUP BY
ShopNo,
DateTransaction,
CASE WHEN CodeModeDePaiement IN (101, 999)
THEN 101
ELSE CodeModeDePaiement END;