Question

我的代码存在一些问题我需要帮助解决问题。

如何让标题仅在结果上方打印一次，如果没有满足标准则根本不打印？
我的代码的else组件不再有效，如果没有其他方案都是真的那么它只用于打印但我更新了它，现在它每次都保持打印。有谁能发现这个问题？

代码：

import Hotels

htl_1= Hotels.Hotels(111,100,1,1)
htl_2= Hotels.Hotels(112,200,2,1)
htl_3= Hotels.Hotels(113,250,2,2)
htl_4= Hotels.Hotels(114,300,3,2)
htl_5= Hotels.Hotels(115,350,3,3)


feeInput=input('Enter maximum per night fee: ')
roomInput=input('Enter minimum number of bedrooms: ')
bathInput=input('Enter minimum number of baths: ')


header='{:10} {:10} {:10} {:10}'.format('Room#','Cost','Rooms','Bathrooms')

print(header)

if int(feeInput)>= htl_1.fee and int(roomInput)<= htl_1.rooms and int(bathInput)<= htl_1.bath:
    print(htl_1.gethtl())
if int(feeInput)>= htl_2.fee and int(roomInput)<= htl_2.rooms and int(bathInput)<= htl_2.bath:
    print(htl_2.gethtl())
if int(feeInput)>= htl_3.fee and int(roomInput)<= htl_3.rooms and int(bathInput)<= htl_3.bath:
    print(htl_3.gethtl())
if int(feeInput)>= htl_4.fee and int(roomInput)<= htl_4.rooms and int(bathInput)<= htl_4.bath:
    print(htl_4.gethtl())
if int(feeInput)>= htl_5.fee and int(roomInput)<= htl_5.rooms and int(bathInput)<= htl_5.bath:
    print(htl_5.gethtl())

else:
    print('Sorry, no rooms available that meet that criteria')

Answer 1

在不知道Hotels模块的情况下，我相信这种语法是正确的。为了使else只在没有if语句都为真时激活，你需要将它们更改为elif（在第一个if语句之后），如图所示。您使用的.format仅在打印状态内工作，如图所示。感谢

import Hotels

htl_1= Hotels.Hotels(111,100,1,1)
htl_2= Hotels.Hotels(112,200,2,1)
htl_3= Hotels.Hotels(113,250,2,2) 
htl_4= Hotels.Hotels(114,300,3,2)
htl_5= Hotels.Hotels(115,350,3,3)

feeInput = int(input('Enter maximum per night fee: '))
roomInput = int(input('Enter minimum number of bedrooms: '))
bathInput = int(input('Enter minimum number of baths: '))

header = True

if feeInput >= htl_1.fee and roomInput <= htl_1.rooms and bathInput<= htl_1.bath: 
    print(htl_1.gethtl())
elif feeInput >= htl_2.fee and roomInput <= htl_2.rooms and bathInput <= htl_2.bath: 
    print(htl_2.gethtl()) 
elif feeInput >= htl_3.fee and roomInput <= htl_3.rooms and bathInput <= htl_3.bath: 
    print(htl_3.gethtl()) 
elif feeInput >= htl_4.fee and roomInput <= htl_4.rooms and bathInput <= htl_4.bath: 
    print(htl_4.gethtl()) 
elif feeInput >= htl_5.fee and roomInput <= htl_5.rooms and bathInput <= htl_5.bath: 
    print(htl_5.gethtl())
else: 
    print('Sorry, no rooms available that meet that criteria')
    header = False

if header == True:
    print('{0} {1} {2} {3}'.format(RoomVar,CostVar,RoomsVar,BathroomsVar))

Answer 2

您需要将if更改为elif，并将标题打印代码移至if块。

任何人都能看到我的代码中的缺陷吗？

2 个答案: