Question

我每周打印数据。我需要在查询中添加一个东西。我想要一周的开始和结束日期以及数据。

目前数据是这样的

        [0] => Array
            (
                [WEEK] => 7

                [total_sub_total] => 110.30
                [total_tax] => 9.92
                [total_restaurant_delivery_fee] => 0
            )


        [0] => Array
            (
                [WEEK] => 8

                [total_sub_total] => 6540.00
                [total_tax] => 1046.40
                [total_restaurant_delivery_fee] => 0
            )

我想要那个星期的日期。例如，它应该是

[0] => Array
                (
                    [WEEK] => 8,
                    [starting_week_date] => 2018-02-21 13:18:10,
                    [ending_week_date] => 2018-02-26 13:18:10,


                    [total_sub_total] => 6540.00
                    [total_tax] => 1046.40
                    [total_restaurant_delivery_fee] => 0
                )

这是代码

public function getWeeklyEarnings($restaurant_id)
    {


        return $this->find('all', array(


            //'contain' => array('OrderMenuItem', 'Restaurant', 'OrderMenuItem.OrderMenuExtraItem', 'PaymentMethod', 'Address','UserInfo','RiderOrder.Rider'),

            'conditions' => array(



                'Order.restaurant_id' => $restaurant_id,
                'Order.status' => 2,
                'Order.created >    DATE_SUB(NOW(), INTERVAL 4 WEEK)'



            ),
            'fields' => array(


                'WEEK(Order.created) AS WEEK',

                'sum(Order.sub_total)   AS total_sub_total',
                'sum(Order.tax)   AS total_tax',
                'sum(Order.restaurant_delivery_fee)   AS total_restaurant_delivery_fee',

            ),
            'group' => array('WEEK(Order.created)'),

            'recursive' => 0

        ));
    }

Answer 1

没有简单的函数可以给出一周的间隔（或一周的开始/结束日期）。您必须手动查找这些日期。
试试这个：

'fields' => array(
    'WEEK(Order.created) AS WEEK',

    'DATE_ADD(Order.created, INTERVAL(1-DAYOFWEEK(Order.created)) DAY) AS week_start',
    'DATE_ADD(Order.created, INTERVAL(7-DAYOFWEEK(Order.created)) DAY) AS week_end',

    'sum(Order.sub_total)   AS total_sub_total',
    'sum(Order.tax)   AS total_tax',
    'sum(Order.restaurant_delivery_fee)   AS total_restaurant_delivery_fee'
)

DAYOFWEEK()函数返回1（星期日）到7（星期六）之间的整数。因此，如果Order.created恰好是星期二，我们会收到以下声明：

DATE_ADD(Order.created, INTERVAL -2 DAY)

这实际上意味着“从Order.created（也就是那个星期的星期日）减去2天以及：

DATE_ADD(Order.created, INTERVAL 4 DAY)

产生该周的星期五的日期。

或者，您可以尝试：

'fields' => array(
    'WEEK(Order.created) AS WEEK',

    'MIN(Order.created) as week_start',
    'MAX(Order.created) as week_end',

    'sum(Order.sub_total)   AS total_sub_total',
    'sum(Order.tax)   AS total_tax',
    'sum(Order.restaurant_delivery_fee)   AS total_restaurant_delivery_fee'
)

但是你必须确保你每周的每一天都有订单。

我希望这会有所帮助。

从mysql获取数据并在几周内对它们进行分组，并显示日期

1 个答案: