Question

以下代码段旨在允许用户输入问题的答案。他们被允许进入四个答案：{是{1}}或y代表“是”，或Y或n代表“否”。该程序应该打印出收到的答案，如果条目有效，否则打印出错误消息。

我只是继续说我回答answer = input("What is your answer? ") if answer == "y" or "Y": print("You answered yes") elif answer == "n" or "N": print("You answered no") else: print("You didn’t enter an acceptable answer")，无论我是yes还是n还是随机的。有人可以向我解释一下吗？

Answer 1

or的优先级不是您所期望的。而是尝试：

answer = input("What is your answer? ")
if answer in ("y", "Y"):
    print("You answered yes")
elif answer in ("n", "N"):
    print("You answered no")
else:
    print("You didn’t enter an acceptable answer")

或者也许喜欢：

answer = input("What is your answer? ")
if answer.lower() == "y":
    print("You answered yes")
elif answer.lower() == "n":
    print("You answered no")
else:
    print("You didn’t enter an acceptable answer")

Answer 2

您的第一个条件将始终返回true，因为"Y"始终是真实的。

尝试：if answer == "y" or answer == "Y":

对其他条件的修改也是如此。

Answer 3

如果您想根据需要立即检查变量，请使用以下内容：

if answer in ["y","Y"]:

如果answer为y或Y

，则会返回True

为什么这个简单的python程序不能按照我想要的方式工作？

3 个答案: