Question

如何将这些数组转换为函数？我无法在网上找到有关如何操作的信息。

$stateArray = array(
    "ct"=>"Connecticut",
    "ma"=>"Massachusetts",
    "nj"=>"New Jersey",
    "ny"=>"New York",
    "ri"=>"Rhode Island");

$destinationArray = array(
    "easterncaribbean"=>"Eastern Caribbean",
    "southerncaribbean"=>"Southern Caribbean",
    "westerncaribbean"=>"Western Caribbean",
    "bermuda"=>"Bermuda",
    "bahamas"=>"Bahamas");

Answer 1

function states() {
  return array(
    "ct"=>"Connecticut",
    "ma"=>"Massachusetts",
    "nj"=>"New Jersey",
    "ny"=>"New York",
    "ri"=>"Rhode Island"
  );
}

function destinations() {
  return array(
    "easterncaribbean"=>"Eastern Caribbean",
    "southerncaribbean"=>"Southern Caribbean",
    "westerncaribbean"=>"Western Caribbean",
    "bermuda"=>"Bermuda",
    "bahamas"=>"Bahamas"
  );
}

$states       = states();
$destinations = destinations();

这是你追求的吗？功能只是可循环使用的代码片段，因此请务必记住这一点。

注意：您的问题没有意义。

Answer 2

创建返回数组的函数：

// function to return State array
function getStateArray() {
    $stateArray = array(
        "ct"=>"Connecticut",
        "ma"=>"Massachusetts",
        "nj"=>"New Jersey",
        "ny"=>"New York",
        "ri"=>"Rhode Island"
    );

    return $stateArray;
}


// function to return Destination array
function getDestinationArray() {
    $destinationArray = array(
        "easterncaribbean"=>"Eastern Caribbean",
        "southerncaribbean"=>"Southern Caribbean",
        "westerncaribbean"=>"Western Caribbean",
        "bermuda"=>"Bermuda",
        "bahamas"=>"Bahamas"
    );

    return $destinationArray;
}

你可以这样调用这些函数：

// call function to get State array
$state = getStateArray();

// this print "Connecticut"
echo "state ct: " . state['ct'];


// call function to get Destination array
$destination = getDestinationArray();

// this print "Eastern Caribbean"
echo "destination easterncaribbean: " . destination['easterncaribbean'];

如何在PHP中将数组转换为函数？

2 个答案: