Question

以下代码不会运行，也不会显示错误消息。请帮忙。另外，我如何添加一个只显示此代码输出的函数？

def main():
 s= ""
 phrase=""
 programdescription(s)
 userinput(phrase)

 #This function displays the program description   
def programdescription(s):
 s = print("This program determines if a word, phrase, or sequence can be read the same backward as forward.")

#This function requests user input for analysis 
def userinput(phrase):
 phrase = input("Enter a word or phrase: ")


def s_phrase(phrase):
 phrase = phrase.upper()
 strippedPhrase = ""
 for char in phrase:
     if (48 <= ord(char) <= 57) or (65 <= ord(char) <= 90):
         strippedPhrase += char
         flag = True
     n = len(strippedPhrase)
     for j in range(int(n / 2)):
         if strippedPhrase[j] != strippedPhrase[n - j - 1]:
             flag = False
             break
     if flag:
         print(phrase, "is a palindrome.")
     else:
         print(phrase, "is not a palindrome.")


main()

Answer 1

好的，问题1是你从不打电话给s_phrase。问题2是s_phrase无法看到短语变量。问题是C是你的缩进搞砸了。问题4更多的事实是，这似乎是一种解决挑战的非常“C”方式。从Spade借用，这是一种更简洁的方式，可以根据原始程序进行格式化。

def main():
    s= ""
    phrase=""
    programdescription(s)
    s_phrase(phrase)

 #This function displays the program description   
def programdescription(s):
    s = print("This program determines if a word, phrase, or sequence can be read the same backward as forward.")

#This function requests user input for analysis 


def s_phrase(phrase):
    phrase = input("Enter a word or phrase: ")
    phrase = phrase.upper()
    r_phrase = phrase[::-1]
    print(r_phrase)
    if phrase == r_phrase:
        print(phrase, "is a palindrome.")
    else:
        print(phrase, "is not a palindrome.")


main()

代码不会运行，也不会显示错误消息

1 个答案: