反转位矩阵

Question

我需要帮助反转一个bitmatrix，我有两个函数，我应该用它。第一个函数交换行，另一个函数将两者相加。我需要在反函数中使用这两个。

void Bitmatrix::Swap_Rows(int r1, int r2) {
    string temp;

    if(r1 < 0 || r2 < 0) return;
    if(r1 > M.size() || r2 > M.size()) return;
    temp = M[r1];
    M[r1] = M[r2];
    M[r2] = temp;
}

void Bitmatrix::R1_Plus_Equals_R2(int r1, int r2) {
    if(r1 < 0 || r2 < 0) return;
    if(r1 >= M.size() || r2 >= M.size()) return;

    for(int i = 0; i < M[1].size(); i++) {
        M[r1][i] = (M[r1][i] + M[r2][i]) % 2;
        M[r1][i] += '0';
    }
}
 //As of now I have this, but not sure how to do the rest.

Bitmatrix *Inverse(Bitmatrix *m) {
    if(m->Rows() != m->Cols()) return NULL; //if not square
    Bitmatrix Inv = new Bitmatrix(m->Rows(), m->Cols());
    for(int i = 0; i < Inv.size(); i++) {
        for(int j = i+1; j < Inv.size(); j++) {
            if(m[i][i] != '1') {
            R1_Plus_Equals_R2(

            }
        }
    }
}