Question

我有一个包含多个ID的日志文件，如下所示：

INFO: [Synth 8-3491] module 'IOBUF' declared at 'C:/Xilinx/Vivado/2017.3/scripts/rt/data/unisim_comp.v:22655' bound to instance 'LED_tri_iobuf_7' of component 'IOBUF' [C:/.../block_design_wrapper.vhd:342]
INFO: [Synth 8-3491] module 'IOBUF' declared at 'C:/Xilinx/Vivado/2017.3/scripts/rt/data/unisim_comp.v:22655' bound to instance 'MAX11603_I2C_scl_iobuf' of component 'IOBUF' [C:/.../block_design_wrapper.vhd:349]
INFO: [Synth 8-3491] module 'IOBUF' declared at 'C:/Xilinx/Vivado/2017.3/scripts/rt/data/unisim_comp.v:22655' bound to instance 'MAX11603_I2C_sda_iobuf' of component 'IOBUF' [C:/.../block_design_wrapper.vhd:356]
INFO: [Synth 8-3491] module 'block_design' declared at 'C:/Projects/.../block_design.vhd:2346' bound to instance 'block_design_i' of component 'block_design' [C:/.../block_design_wrapper.vhd:363]
---------------------------------------------------------------------------------
Starting RTL Elaboration : Time (s): cpu = 00:00:07 ; elapsed = 00:00:07 . Memory (MB): peak = 491.250 ; gain = 104.844
---------------------------------------------------------------------------------
INFO: [Synth 8-638] synthesizing module 'block_design' [C:/Projects/.../block_design.vhd:2469]
INFO: [Synth 8-638] synthesizing module 'block_design_axi_mem_intercon_0' [C:/Projects/.../block_design.vhd:1403]
INFO: [Synth 8-638] synthesizing module 'm00_couplers_imp_1Y96WCF' [C:/Projects/.../block_design.vhd:81]
INFO: [Synth 8-3491] module 'block_design_auto_pc_0' declared at 'C:/.../block_design_auto_pc_0_stub.vhdl:5' bound to instance 'auto_pc' of component 'block_design_auto_pc_0' [C:/Projects/.../block_design.vhd:267]
INFO: [Synth 8-638] synthesizing module 'block_design_auto_pc_0' [C:/.../block_design_auto_pc_0_stub.vhdl:71]
INFO: [Synth 8-256] done synthesizing module 'm00_couplers_imp_1Y96WCF' (2#1) [C:/Projects/.../block_design.vhd:81]
INFO: [Synth 8-638] synthesizing module 'm01_couplers_imp_1SYGEF3' [C:/Projects/.../block_design.vhd:422]
INFO: [Synth 8-256] done synthesizing module 'm01_couplers_imp_1SYGEF3' (3#1) [C:/Projects/.../block_design.vhd:422]
INFO: [Synth 8-638] synthesizing module 'm02_couplers_imp_1MNJOVZ' [C:/Projects/.../block_design.vhd:611]

每个INFO行都包含来自特定工具（此处为Synth）和ID xx-yyyy的消息。

如何使用Bash和Git-Bash中提供的工具提取日志文件中所有出现的ID？最后，我需要将输入日志文件拆分为多个文件，仅包含属于同一ID的邮件。因此，ID列表必须是唯一的。

我在PowerShell中已经完成了相同的脚本编写。此方法使用正则表达式匹配和为每个新ID扩展的ID数组。

它分3个步骤处理日志文件：

按类别分割日志文件
收集唯一的邮件ID列表
将每个分类的日志文件拆分为每个消息ID的单独文件

主要问题是：如何创建此唯一邮件ID列表？（第2步）

PowerShell脚本：

[CmdletBinding()]
Param(
  [Parameter(Mandatory=$True,Position=1)]
  [string]$ReportFile
)

$SynthesisLogFile = Get-Item $ReportFile
$SynthesisLog = $SynthesisLogFile.BaseName

$Categories = @("INFO", "CRITICAL WARNING", "WARNING", "ERROR")

foreach ($Cat in $Categories)
{ Write-Host "Extracting category $Cat from $ReportFile ..."
  $line=0
  cat ".\$ReportFile" | %{ $line=$line+1; if ($_ -match "^$Cat") { "$line`t$_"} } > ".\$SynthesisLog.$Cat.log"

  $IDs = @();
  cat ".\$SynthesisLog.$Cat.log" | %{ $m = $_ -match "^\d+\t$($Cat): \[(\w+) (\d+-\d+)\]"; $mm = $Matches[2]; if ($IDs -notcontains $mm) {$IDs = $IDs + $mm } }
  foreach ($ID in $IDs)
  { Write-Host "  Extracting ID: $ID ..."
    cat ".\$SynthesisLog.$Cat.log" | Select-String "$ID" > ".\$SynthesisLog.$Cat.$ID.log"
  }
}

这是我目前的Bash脚本：

#! /bin/bash

LOGFILE=$(basename "$1")
PREFIX="${LOGFILE%.*}"

for CATEGORY in INFO WARNING "CRITICAL WARNING" ERROR; do
  CATEGORY_FILE="$PREFIX.$CATEGORY.log"
  echo "Extracting category '$CATEGORY' from '$LOGFILE' ..."
  grep -n "^$CATEGORY: " "$1" > "$CATEGORY_FILE"

  if [[ -s $CATEGORY_FILE ]]; then
    echo "  File contains data"
  else
    echo "  Deleting empty output file for category '$CATEGORY'"
    rm "$CATEGORY_FILE"
  fi
done

以下是我在answer下改进的最终Bash脚本：

#! /bin/bash

LOGFILE=$(basename "$1")
PREFIX="${LOGFILE%.*}"

for CATEGORY in INFO WARNING "CRITICAL WARNING" ERROR; do
  CATEGORY_FILE="$PREFIX.$CATEGORY.log"
  echo "Extracting category '$CATEGORY' from '$LOGFILE' ..."
  grep -n "^$CATEGORY: " "$1" > "$CATEGORY_FILE"

  if [[ -s $CATEGORY_FILE ]]; then
    for ID in $(grep -P "^\d+:$CATEGORY: \[\w+ \d+-\d+\]" "$CATEGORY_FILE" | awk -F' ' '{print $3}' | tr -d ']' | sort | uniq); do
      ID_FILE="$PREFIX.$CATEGORY.$ID.log"
      echo "  Extracting ID: $ID ..."
      grep "$ID" "$CATEGORY_FILE" > "$ID_FILE"
    done
  else
    echo "  Deleting empty output file for category '$CATEGORY'"
    rm "$CATEGORY_FILE"
  fi
done

Answer 1

试试这个......

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如何在日志文件中获取所有使用的ID

1 个答案: