不知道如何阅读这种json格式

时间:2018-03-03 14:27:57

标签: javascript json

我从来没有从网址或任何像这样建造的东西中读取json的麻烦:

{ success: true,
  name: 'Dekirai',
  clan: null,
  level: 7,
  exp: 3193,
  playtime: 0,
  tdrate: 0,
  kdrate: 0,
  matches_played: 0,
  matches_won: 0,
  matches_lost: 0,
  last_online: '2018-03-02T23:00:00.000Z',
  views: 1,
  favorites: 0,
  fame: 0,
  hate: 0 }

但是json我现在在这里使用了方括号:

[ { id: 23,
    name: 'AeriaGames Login',
    player_limit: -1,
    player_online: -1,
    state: 2,
    last_update: '2018-02-14T16:22:28.000Z' },
  { id: 1,
    name: 'Auth',
    player_limit: -1,
    player_online: -1,
    state: 2,
    last_update: '2018-03-03T14:17:22.000Z' },
  { id: 10,
    name: 'English 1 (Europe)',
    player_limit: 4000,
    player_online: 871,
    state: 2,
    last_update: '2018-03-03T14:17:22.000Z' },
  { id: 11,
    name: 'English 2 (Europe)',
    player_limit: 4000,
    player_online: 48,
    state: 2,
    last_update: '2018-03-03T14:17:22.000Z' },
  { id: 12,
    name: 'English 3 (North America)',
    player_limit: 4000,
    player_online: 54,
    state: 2,
    last_update: '2018-03-03T14:17:22.000Z' } ]

我现在的问题是:

我如何阅读" player_online"价值来自" id:10"?

3 个答案:

答案 0 :(得分:3)

let player_online = yourObject.find(el => el.id === 10).player_online

答案 1 :(得分:0)

您可以使用filter方法。这将返回匹配属性的数组。然后使用dot运算符获取属性值



var x = [{
    id: 23,
    name: 'AeriaGames Login',
    player_limit: -1,
    player_online: -1,
    state: 2,
    last_update: '2018-02-14T16:22:28.000Z'
  },
  {
    id: 1,
    name: 'Auth',
    player_limit: -1,
    player_online: -1,
    state: 2,
    last_update: '2018-03-03T14:17:22.000Z'
  },
  {
    id: 10,
    name: 'English 1 (Europe)',
    player_limit: 4000,
    player_online: 871,
    state: 2,
    last_update: '2018-03-03T14:17:22.000Z'
  },
  {
    id: 11,
    name: 'English 2 (Europe)',
    player_limit: 4000,
    player_online: 48,
    state: 2,
    last_update: '2018-03-03T14:17:22.000Z'
  },
  {
    id: 12,
    name: 'English 3 (North America)',
    player_limit: 4000,
    player_online: 54,
    state: 2,
    last_update: '2018-03-03T14:17:22.000Z'
  }
]

var getPlayerOnline = x.filter(function(item) {
  return item.id === 10 // will return object where id is 10

})[0].player_online;

console.log(getPlayerOnline)




答案 2 :(得分:0)

您可以使用find查找player_online的值。



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