Question

我想要你的帮助。请帮助。

错误：（63,0）无法设置只读属性的值＆quot; outputFile＆＃39; for apkVariantOutputImpl_Decorated {apkData = Main {type = MAIN，fullName = debug，filters = []}}，类型为com.android.build.gradle.internal.api.ApkVariantOutputImpl。打开文件

applicationVariants.all { variant ->
    variant.outputs.each { output ->
        def file = output.outputFile
        output.outputFile = new File(file.parent, "kickmaterial-" + defaultConfig.versionName + ".apk")
    }
}

android版本是3.0.1 请你的帮助。

Answer 1

从gradle插件3.0开始，您无法像documentation中所说的那样使用each()：

使用Variant API来操作变量输出新插件。它仍然适用于简单的任务，例如更改APK 在构建期间命名，如下所示：

// If you use each() to iterate through the variant objects,
// you need to start using all(). That's because each() iterates
// through only the objects that already exist during configuration time—
// but those object don't exist at configuration time with the new model.
// However, all() adapts to the new model by picking up object as they are
// added during execution.

android.applicationVariants.all { variant ->
    variant.outputs.all {
        outputFileName = "${variant.name}-${variant.versionName}.apk"
    }
}

因此，您需要制作如下代码的块代码：

android.applicationVariants.all { variant ->
    variant.outputs.all {
        outputFileName = "$kickmaterial-${variant.versionName}.apk"
    }
}

错误：（63,0）无法设置只读属性的值＆quot; outputFile＆＃39;

1 个答案: