在星号前删除3个或更少字符的行

Question

我在Google Spreadsheets中有一个脚本，用于删除包含4个或更多数字的alls行。我想修改它以删除在星号标志之前具有3个或更少字符（数字或其他）的所有行，*。

以下是当前形式的脚本：

function removeRows() {
  var sheet = SpreadsheetApp.getActiveSheet();
  var rows = sheet.getDataRange();
  var numRows = rows.getNumRows();
  var values = rows.getValues();
  var rowsDeleted = 0;
  var val = sheet.getRange(2, 1, lr-1, 2).getValues();
  var lr = sheet.getLastRow()

  for (var i = 0; i <= numRows - 1; i++) {
    var row = values[i];
    var str = row[0].replace(/\D/g, '')//extract the numbers
    var len = str.length // determine lenght of number string
    if(len >=4 ){ //if 4 or more numbers delete
      sheet.deleteRow((parseInt(i)+1) - rowsDeleted);
      rowsDeleted++;
    }
  }

  for (var i = 0; i <= val.length-1; i++) {
    var str=val[i][0].split(/[*]/)//split at *
    var numStr = str[0].replace(/\D/g, '');
    var len = numStr.length // determine length of string of first split

    if(len <=3 ){ //if 3 or less, delete
      sheet.deleteRow((parseInt(i)+1) - rowsDeleted);
      rowsDeleted++;
    }
  }  
}

Answer 1

您可以使用https://kubernetes.io/docs/reference/generated/kubernetes-api/v1.9/#execaction-v1-core来测试单元格内容中是否存在该字符，而不是split字符处*字符。如果有*，则返回的整数将为0或更多。值为4或更多表示搜索字符前面有4个或更多字符，而值0到3表示前面有0到3个字符。

此代码段假设您的工作表数据位于名为val的数组数组中（就像您在上面发布的代码中所做的那样）。

var colIndex = 0; // Which column in the range should be checked for an *.
for(var i = 0; i < val.length; ++i) {
  var charBefore = String(val[i][colIndex]).indexOf("*");
  if(charBefore < 4 && charBefore >= 0) {
    /*
     * There are 3 or fewer characters preceding the asterisk.
     * Add code in this block to work with i, val, val[i], or val[i][colIndex]
     * for this specific case.
     */
  } else {
    /*
     * There was no asterisk in the cell, or it was preceded by 4+ characters.
     * Add code to this block (or remove the else block entirely, if nothing is to
     * be done with rows / cells that did not meet the specified asterisk criteria.
     */
  }
}

Answer 2

在您的代码段中，在分割行的值后，您没有提取数字。 试试这个： -

for (var i = 0; i <= val.length-1; i++) {
var str=val[i][0].split(/[*]/)//split at *
var numStr = str[0].replace(/\D/g, '');
var len=numStr.length // determine length of string of first split

if(len <=3 ){ //if 3 or less, delete
  sheet.deleteRow((parseInt(i)+1) - rowsDeleted);
  rowsDeleted++;
}