Question

所以我正在尝试制作一个打印出所有完美整数高达10000的程序，我已经能够让我的程序能够做到这一点，但我似乎无法正确安排打印出来;我想让它显示如下：

6：1 2 3

28：1 2 4 7 14

496：1 2 4 8 16 31 62 124 248

8128：1 2 4 8 16 32 64 127 254 508 1016 2032 4064

但我现在正在接受这个：

8128：4064

8128：2032

8128：1016

8128：508

8128：254

8128：127

8128：64

8128：32

8128：16

8128：8

8128：4

8128：2

8128：1

我已经尝试了我能想到的一切，但似乎无法做到正确：C，

（ps：它为每个完美整数垂直显示输出：c）请帮助

#include <iostream>
#include <string>

using namespace std;

void perfect(int number)
{

int DivTotal = 0, Div;
//string


    for (int halfNum = number / 2; halfNum >= 1; halfNum--)
    {

        Div = number % halfNum;

        if (Div == 0)
        DivTotal += halfNum;

    }



    if (DivTotal == number)
    {
        for (int halfNum = number / 2; halfNum >= 1; halfNum--)
        {

            Div = number % halfNum;

            if (Div == 0)
            cout<< number << ":"<< halfNum<<endl;
            //cout<<endl;

        }

    }


}



int main()
{

    cout << "Perfect numbers between 1 and 10000 are:" << endl;

    for (int count = 1; count <= 10000; count++)
    {
         perfect(count);
        // cout << perfect<< ":" << endl;
    }

 system("Pause");
 }

Answer 1

迄今为止的微调变体给出答案：

if (DivTotal == number)
{
    // needs to be moved out of loop for not being printed with every number
    // additionally, 1 is always a divisor, so we can add it right here:
    std::cout << number << ": 1";

    for(int i = 2; i * i <= number; ++i)  // counting up to have order right!
                 //^^^^^ until sqrt only...
    {
        if(number % i == 0)
            std::cout << ", " << i;
                        //^ with or without comma...
    } 
    std::cout << std::endl;
}

Answer 2

我希望这有助于

if (DivTotal == number)
{
    char toPrint[100];
    char toAdd[10];
    sprintf(toPrint,"%d:",number);
    for (int halfNum = number / 2; halfNum >= 1; halfNum--)
    {

        Div = number % halfNum;

        if (Div == 0)
        {
             sprintf(toAdd," %d ",halfNum);
             strcat(toPrint,toAdd);
        }
    }
    cout<< toPrint<<endl;
    //cout<<endl;
}

使用sprintf和strcat remeber包含stdio.h

如何安排打印出我的程序水平循环而不重复

2 个答案: