Question

我正在使用Django和REST框架。我正在定义一个APIView，在其中，我使用create（）创建一个ORM对象。我传递给create函数的一个字段是失败的，说它不是一个有效的关键字参数。这是我正在添加的新领域。该字段存在于模型和序列化程序中。另一个类似的新领域并没有失败。

回溯：

Internal Server Error: /api/new_thing
Traceback (most recent call last):
  File "/local/lib/python2.7/site-packages/django/core/handlers/base.py", line 132, in get_response
    response = wrapped_callback(request, *callback_args, **callback_kwargs)
  File "/local/lib/python2.7/site-packages/django/views/decorators/csrf.py", line 58, in wrapped_view
    return view_func(*args, **kwargs)
  File "/local/lib/python2.7/site-packages/django/views/generic/base.py", line 71, in view
    return self.dispatch(request, *args, **kwargs)
  File "/local/lib/python2.7/site-packages/rest_framework/views.py", line 466, in dispatch
    response = self.handle_exception(exc)
  File "/local/lib/python2.7/site-packages/rest_framework/views.py", line 463, in dispatch
    response = handler(request, *args, **kwargs)
  File "/other_app/rest_apis.py", line 336, in post
    flag=false
  File "/local/lib/python2.7/site-packages/django/db/models/manager.py", line 127, in manager_method
    return getattr(self.get_queryset(), name)(*args, **kwargs)
  File "/local/lib/python2.7/site-packages/django/db/models/query.py", line 346, in create
    obj = self.model(**kwargs)
  File "/local/lib/python2.7/site-packages/django/db/models/base.py", line 480, in __init__
    raise TypeError("'%s' is an invalid keyword argument for this function" % list(kwargs)[0])
TypeError: 'doohickeys' is an invalid keyword argument for this function

API查看：

class NewThing(APIView):

    renderer_classes = (JSONRenderer,)
    serializer_class = StuffSerializer

    @detail_route(methods=['POST'])
    def post(self, request, pk, format=None):
        # do stuff
        whatsits_list = [] # list of ORM objects
        doohickeys_list = [] # list of ORM objects
        thing = Thing.objects.create(
            whatsits=whatsits_list, # this is not failing
            doohickeys=doohickeys_list, # this is failing
            flag=false
        )
        # return some stuff

型号：

from django.db import models
from other_app.models import Doohickey, Whatsit

class Thing(models.Model):
    whatsits = models.ManyToManyField('other_app.Whatsit', related_name='things', blank=True)    
    doohickeys = models.ManyToManyField('other_app.Doohickey', related_name='things', blank=True)
    flag = models.BooleanField(default=True)

串行：

class StuffSerializer(serializers.ModelSerializer):
    doohickeys = serializers.PrimaryKeyRelatedField(queryset=Doohickey.objects.all(), many=True, allow_empty=True)

    class Meta:
        model = Stuff
        fields = ('id',
                  'doohickeys',
                  'whatsits',
                  'public',
        )

知道为什么我在doohickey键上出错了吗？我已经尝试使用调试器来跟踪代码，看起来它是REST框架APIView类中的dispatch（）函数捕获的异常。

谢谢！

Answer 1

在保存对象之前，您不能使用多对多字段，因为它实际上是一个使用每边对象ID的直通表。因此，首先创建对象，然后添加doohickeys。

thing = Thing.objects.create(...)
thing.doohickeys.add(*doohickeys_list)

请注意，你所做的事情很奇怪。 django-rest-framework的重点在于你使用了序列化器，它为你处理了所有这些逻辑 - 你已经定义了一个序列化器，但是你没有使用它，你似乎完全绕过了它。 / p>

Django REST框架：“无效的关键字参数”错误，但模型中存在字段

1 个答案: