我看到很多应用程序都在做短信弹出窗口。为什么我不能让我的应用程序工作?如果收到短信,我希望它能在屏幕上弹出。
这是我的代码:
public class NotifySMSReceived extends Activity
{
private static final String LOG_TAG = "SMSReceiver";
public static final int NOTIFICATION_ID_RECEIVED = 0x1221;
static final String ACTION = "android.provider.Telephony.SMS_RECEIVED";
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
IntentFilter filter = new IntentFilter(ACTION);
this.registerReceiver(mReceivedSMSReceiver, filter);
}
private void displayAlert()
{
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setMessage("Are you sure you want to exit?").setCancelable(
false).setPositiveButton("Yes",
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
dialog.cancel();
}
}).setNegativeButton("No",
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
dialog.cancel();
}
});
AlertDialog alert = builder.create();
alert.show();
}
private final BroadcastReceiver mReceivedSMSReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
String action = intent.getAction();
if (ACTION.equals(action))
{
//your SMS processing code
displayAlert();
}
}
};
}
答案 0 :(得分:0)
我认为问题在于上下文对象。从,
onReceive(上下文上下文,意图意图)
您应该将onRecive中收到的上下文传递给..
private void displayAlert(Context context )
然后, 改变,
AlertDialog.Builder builder = new AlertDialog.Builder(this);
以强>
AlertDialog.Builder builder = new AlertDialog.Builder( context );
现在它应该起作用了。这有帮助。
干杯。