Jasmine SpyObj不返回模拟对象

时间:2018-03-01 10:12:18

标签: javascript angular jasmine2.0

我正在尝试测试以下服务。

@Injectable()
export class TranslationService {

  language = 'NL';

  constructor(contextService: ContextService) {
    let context = contextService.getContext();
    this.language = context.language;
  }
}

实际测试:

describe('TranslationService', () => {

  let service: TranslationService;
  let contextServiceSpy: jasmine.SpyObj<ContextService>;

  beforeEach(() => {

    const contextSpy = jasmine.createSpyObj('ContextService', ['getContext']);
 
    TestBed.configureTestingModule({
      providers: [
        TranslationService,
        {provide: ContextService, useValue: contextSpy}]
    });

    service = TestBed.get(TranslationService);
    contextServiceSpy = TestBed.get(ContextService);
  
  });

  it('should create an instance', () => {

    const context: Context = {
      language: 'EN'
    };

    contextServiceSpy.getContext.and.returnValue(context);

    expect(service).toBeDefined();
    expect(contextServiceSpy.getContext.calls.count()).toBe(1, 'spy method was called once');
    expect(contextServiceSpy.getContext.calls.mostRecent().returnValue).toBe(context);
  });

});

现在,当我运行测试时,它返回错误:

TypeError: Cannot read property 'language' of undefined

这意味着间谍没有返回我的模拟上下文。但我不知道为什么不是。任何人吗?

我使用了https://angular.io/guide/testing#service-tests

角度5.2.4

jasmine 2.8.0

1 个答案:

答案 0 :(得分:2)

在模拟getContext存根之前调用服务构造函数。

应该是:

contextServiceSpy = TestBed.get(ContextService);
contextServiceSpy.getContext.and.returnValue(context);
service = TestBed.get(TranslationService);