通过ViewModel
商店我获取此JSON数据;
{
"success": true,
"msg": "OK",
"count": 2,
"data": [
{
"firstname": "BLA",
"lastname": "BLALA",
"isactive": true,
...
},
{
"firstname": "BLAAA",
"lastname": "BLALAAA",
"isactive": false,
...
}
我在一个panel
上有两个网格,其中一个仅使用isactive: true
字段加载数据,其他网格只会加载false
。 那么我需要在何处以及如何过滤商店以将指定数据加载到网格?
这是VM;
Ext.define('MyApp.view.ListingVM', {
extend: 'Ext.app.ViewModel',
alias: 'viewmodel.listing',
requires: [...],
reference: 'loyaltyvm',
stores: {
// Should I define the filter on here?
bonusTrans: {
storeId: 'bonusTrans',
// reference: 'bonusTrans',
model: 'MyApp.model.BonusTrans',
autoLoad: true,
session: true,
pageSize: MyApp.Globals.LIST_PAGE_SIZE
}
}
});
这是panel
网格示例,其中定义了两个网格。我已经尝试了几种方法来获取store
并过滤但不能成功;
getColumns: function () {
var me = this;
var panelItems = [
{
xtype: 'container',
layout: {type: 'hbox', align: 'stretch', pack: 'start'},
items: [
xtype: 'bonustrans',
flex: 1,
title: 'Current Bonus',
getListCols: function () {
var me = this;
debugger;
// var activeStore = Ext.getStore('bonusTrans');
// var activeStore = me.viewModel.get('bonusTrans');
// var view = me.getView();
// var vm = view.getViewModel();
// var vm.getStore('bonusTrans')
// var activeStore = me.getViewModel().getStore('bonusTrans');
var activeStore = me.getViewModel('loyaltyvm').getStores('bonusTrans');
activeStore.filter('isactive', 'true');
var listCols = [
{
xtype: 'firstnamecol',
flex: 1
},
{
xtype: 'checkoutcol'
},
{
xtype: 'bonustotalcol'
}
];
return listCols;
}
//... other Grid is just defined below of this line and it should loads data only with 'isactive' field is false.
答案 0 :(得分:2)
使用链式商店,fiddle:
Ext.application({
name : 'Fiddle',
launch : function() {
new Ext.container.Viewport({
layout: {
type: 'hbox',
align: 'stretch'
},
viewModel: {
stores: {
everything: {
autoLoad: true,
proxy: {
type: 'ajax',
url: 'data1.json'
}
},
active: {
type: 'chained',
source: '{everything}',
filters: [{
property: 'active',
value: true
}]
},
inactive: {
type: 'chained',
source: '{everything}',
filters: [{
property: 'active',
value: false
}]
}
}
},
items: [{
flex: 1,
xtype: 'gridpanel',
title: 'Active',
bind: '{active}',
columns: [{
dataIndex: 'name'
}]
}, {
flex: 1,
xtype: 'gridpanel',
title: 'Inactive',
bind: '{inactive}',
columns: [{
dataIndex: 'name'
}]
}]
});
}
});
答案 1 :(得分:2)
连锁店的方式肯定是最好的, here you can see a working fiddle on classic
这是代码:
Ext.application({
name: 'Fiddle',
launch: function () {
var storeAll = Ext.create('Ext.data.Store', {
storeId: 'storeAll',
fields: [{
name: 'firstname'
}, {
name: 'lastname'
}, {
name: 'active'
}],
data: [{
firstname: 'test1',
lastname: 'test1',
active: true
}, {
firstname: 'test2',
lastname: 'test2',
active: true
}, {
firstname: 'test3',
lastname: 'test3',
active: false
}]
}),
chainedStoreActive = Ext.create('Ext.data.ChainedStore', {
source: storeAll,
filters: [{
property: 'active',
value: true
}]
}),
chainedStoreNoActive = Ext.create('Ext.data.ChainedStore', {
source: storeAll,
filters: [{
property: 'active',
value: false
}]
});
Ext.create({
xtype: 'viewport',
layout: {
type: 'vbox',
align: 'stretch'
},
items: [{
xtype: 'gridpanel',
title: 'grid ALL',
store: storeAll,
columns: [{
text: 'First Name',
dataIndex: 'firstname'
}, {
text: 'Last Name',
dataIndex: 'lastname'
}],
flex: 1
}, {
xtype: 'gridpanel',
title: 'grid active',
store: chainedStoreActive,
columns: [{
text: 'First Name',
dataIndex: 'firstname'
}, {
text: 'Last Name',
dataIndex: 'lastname'
}],
flex: 1
}, {
xtype: 'gridpanel',
title: 'grid inactive',
store: chainedStoreNoActive,
columns: [{
text: 'First Name',
dataIndex: 'firstname'
}, {
text: 'Last Name',
dataIndex: 'lastname'
}],
flex: 1
}],
renderTo: Ext.getBody()
});
}
});
全局或“allelements”商店需要是一个全局商店,链接的商店可以在视图的视图模型中创建。