Question

当我尝试将某些数据插入表格时，我收到此错误：

'latin-1' codec can't encode character '\u2019' in position 8: ordinal not in range(256)

问题在于我没有在任何地方使用latin-1 - 表格为utf8mb4，排序规则为utf8mb4_unicode_520_ci。为了确保这是我检查过的情况：

mysql> SHOW FULL COLUMNS FROM CustomCommands_u1eae585f88c8ab055a227488b2b5adb1;
+-----------------+---------------+------------------------+------+-----+---------+-------+---------------------------------+---------+
| Field           | Type          | Collation              | Null | Key | Default | Extra | Privileges                      | Comment |
+-----------------+---------------+------------------------+------+-----+---------+-------+---------------------------------+---------+
| command_id      | int(10)       | NULL                   | YES  |     | NULL    |       | select,insert,update,references |         |
| text            | varchar(2000) | utf8mb4_unicode_520_ci | YES  |     | NULL    |       | select,insert,update,references |         |
| contentMetadata | varchar(1000) | utf8mb4_unicode_520_ci | YES  |     | NULL    |       | select,insert,update,references |         |
| contentType     | int(3)        | NULL                   | YES  |     | NULL    |       | select,insert,update,references |         |
+-----------------+---------------+------------------------+------+-----+---------+-------+---------------------------------+---------+

果然它绝对是utf8mb4。这是我用来将数据插入表中的python代码：

def _add_cc(self, rid, text, contentMetadata, contentType):
    query = "INSERT INTO `CustomCommands_%s` (`command_id`,`text`,`contentMetadata`,`contentType`) VALUES (%s,%s,%s,%s)" % (self._mid,'%s','%s','%s','%s')
    tup = (rid,text,str(contentMetadata),contentType)
    print(query)
    print(tup)
    self._cur.execute(query, tup)

它打印的查询是：

INSERT INTO `CustomCommands_u1eae585f88c8ab055a227488b2b5adb1` (`command_id`,`text`,`contentMetadata`,`contentType`) VALUES (%s,%s,%s,%s)

元组是：

(1470115915, '@Lil Cap’n Jack ', '{\'MENTION\': \'{"MENTIONEES":[{"M":"u98de557a46645dc6cd7583e538e1ae40","S":"0","E":"15"}]}\'}', 0)

因为一切都是utf8mb4，我不确定为什么我会收到latin-1编解码器错误。我甚至运行下面的代码，它仍然给了我同样的错误。

db = MySQLdb.connect(host="localhost", user="root", passwd="password", db="database")
db.autocommit(True)
cur = db.cursor()

tables = []
cur.execute("SHOW TABLES")
for row in cur.fetchall():
    tables.append(row[0])

for table in tables:
    cur.execute("ALTER TABLE %s CONVERT TO CHARACTER SET utf8mb4 COLLATE utf8mb4_unicode_520_ci" % table)

所以，不知道该怎么做。

Answer 1

归功于Writing UTF-8 String to MySQL with Python以及分享该帖子的人（https://stackoverflow.com/users/5871602/daniel-e，idk如何实际标记您）

当我设置连接时，而不是这样做：

db = MySQLdb.connect(host="localhost", user="root", passwd="password", db="database")

我应该这样做：

db = MySQLdb.connect(host="localhost", user="root", passwd="password", db="database", charset="utf8mb4")

由于某种原因，在连接中指定字符集会产生差异。

即使我使用utf8mb4，MYSQL也会给我一个latin-1编解码器错误

1 个答案: