Question

当我点击通知时，我希望它打开应用程序的通知viewController。所有代码都在AppDelegate.m

中

我有一个函数来查找topMostController

- (UIViewController *)topMostController {
    UIViewController *topController = [UIApplication sharedApplication].keyWindow.rootViewController;
    while (topController.presentedViewController) {
        topController = topController.presentedViewController;
    }
    return topController;
}

然后还有另一个显示通知viewController的函数

    UINavigationController *navigationController = (UINavigationController *)[self topMostController];

    UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"MainStoryBoard" bundle:nil];

    MyViewController *myController = [storyboard instantiateViewControllerWithIdentifier:@"MyViewController"];

    [navigationController pushViewController:myController animated:YES];

如果应用程序打开，它可以正常工作。但是，当应用程序关闭时，如果我单击通知，它将崩溃。错误是

Fatal Exception: NSInvalidArgumentException
-[ViewController pushViewController:animated:]: unrecognized selector sent to instance

我认为没有topMostController或者navigationController无效。我需要使用UINavigationController，因为我想要一个“后退”按钮返回页面（主页面）而不是关闭应用程序。在这种情况下，如何使topMostController有效？我应该在didFinishLaunchingWithOptions函数中创建一些东西吗？感谢。

Answer 1

您需要分配根视图控制器

   self.navigationController = RootNavigationControllerViewController(rootViewController: HomeViewController.init())



    self.window?.rootViewController =  self.navigationController
    self.window?.makeKeyAndVisible()

当ios应用关闭时，Firebase通知点击崩溃

1 个答案: