我是Javascript的新手，我必须过滤一个数组，所以我用谷歌搜索，花了我的时间找到解决方案，但没有人帮助我.PLZ帮助我。 我有以下数组，这是查询的结果：
"clause": [
{
"clause_id": 1,
"clause_text": "A",
"clause_item_id": 1,
"item_text": "this text is related to clause 1 ",
"item_photo": ""
},
{
"clause_id": 2,
"clause_text": "B",
"clause_item_id": 2,
"item_text": "this text is related to clause 2 ",
"item_photo": ""
},
{
"clause_id": 2,
"clause_text": "B",
"clause_item_id": 3,
"item_text": "this text is related to clause 2",
"item_photo": ""
},
{
"clause_id": 2,
"clause_text": "B",
"clause_item_id": 4,
"item_text": "this text is related to clause 2",
"item_photo": ""
},
{
"clause_id": 3,
"clause_text": "C",
"clause_item_id": 5,
"item_text": "this text is related to clause 3",
"item_photo": ""
},
{
"clause_id": 3,
"clause_text": "C",
"clause_item_id": 6,
"item_text": "this text is related to clause 3",
"item_photo": ""
},
{
"clause_id": 3,
"clause_text": "C",
"clause_item_id": 7,
"item_text": "this text is related to clause 3",
"item_photo": ""
}
]
我想改变它的格式。并将其作为JSON响应发送给客户端。所以上面的数组应该通过子句id进行过滤，该子句重复多次。我想重新格式化数组，避免重复一些数组元素。所以我想要的最终数组是：
{ "clauses": [
{
"cls": {
"clause_id": 1,
"clause_text": "A"
},
"items": [
{
"claud_item_id": 1,
"item_text": "this text is related to clause 1",
"item_photo": ""
}
]
},
{
"cls": {
"clause_id": 2,
"clause_text": "B"
},
"items": [
{
"claud_item_id": 2,
"item_text": "this text is related to clause 2",
"item_photo": ""
},
{
"claud_item_id": 3,
"item_text": "this text is related to clause 2",
"item_photo": ""
},
{
"claud_item_id": 4,
"item_text": "this text is related to clause 2",
"item_photo": ""
}
]
},
{
"cls": {
"clause_id": 3,
"clause_text": "C"
},
"items": [
{
"claud_item_id": 5,
"item_text": "this text is related to clause 3",
"item_photo": ""
},
{
"claud_item_id": 6,
"item_text": "this text is related to clause 3",
"item_photo": ""
},
{
"claud_item_id": 7,
"item_text": "this text is related to clause 3",
"item_photo": ""
}
]
}
]
}
PLZ帮帮我
答案 0 :(得分：0)
var item_val = item_val = {"clause": [
{
"clause_id": 1,
"clause_text": "A",
"clause_item_id": 1,
"item_text": "this text is related to clause 1 ",
"item_photo": ""
},
{
"clause_id": 2,
"clause_text": "B",
"clause_item_id": 2,
"item_text": "this text is related to clause 2 ",
"item_photo": ""
},
{
"clause_id": 2,
"clause_text": "B",
"clause_item_id": 3,
"item_text": "this text is related to clause 2",
"item_photo": ""
},
{
"clause_id": 2,
"clause_text": "B",
"clause_item_id": 4,
"item_text": "this text is related to clause 2",
"item_photo": ""
},
{
"clause_id": 3,
"clause_text": "C",
"clause_item_id": 5,
"item_text": "this text is related to clause 3",
"item_photo": ""
},
{
"clause_id": 3,
"clause_text": "C",
"clause_item_id": 6,
"item_text": "this text is related to clause 3",
"item_photo": ""
},
{
"clause_id": 3,
"clause_text": "C",
"clause_item_id": 7,
"item_text": "this text is related to clause 3",
"item_photo": ""
}
]
}
var result_val = {};
item_val['clause'].forEach(function(val){
var t = {'item_photo': val['item_photo'],'item_text':val['item_text'],'clause_item_id':val['clause_item_id']}
if(!(val['clause_id'] in result_val))
result_val[val['clause_id']] = {}
if(!(val['clause_text'] in result_val[val['clause_id']]))
result_val[val['clause_id']][val['clause_text']] = {}
if('item' in result_val[val['clause_id']][val['clause_text']]){
result_val[val['clause_id']][val['clause_text']]['item'].push(t)
}else{
result_val[val['clause_id']][val['clause_text']]['item'] = []
result_val[val['clause_id']][val['clause_text']]['item'].push(t)
}
})
console.log(result_val)
答案 1 :(得分：0)
所以你可以构建一个新的javascript对象，但是如果你有＆＃39; items＆＃39;的对象属性，它可能会很棘手。在同一个物体中重复过来。我通过使结果有一系列项目来解决这个问题。
该算法使用双循环，因此对于大型json尺寸来说它会很昂贵，但它可以工作。
这里的代码和输出假设要排序的json对象被命名为＆＃39; obj＆＃39;。
var newObj = {"clause":[]};
var i,j;
for(i = 0; i < obj.clause.length; i++){
var current = obj.clause[i];
for(j = 0; j < newObj.clause.length; j++){
if(newObj.clause[j].cls && newObj.clause[j].cls["clause_id"] == current["clause_id"]){
var subObj = {"claud_item_id": current["clause_item_id"], "item_text": current["item_text"], "item_photo": current["item_photo"]};
newObj.clause[j].items.push(subObj);
break;
}
}
if(j == newObj.clause.length){
var subObj = {"cls": {"clause_id": current["clause_id"], "clause_text": current["clause_text"]},
"items": [{"claud_item_id": current["clause_item_id"], "item_text": current["item_text"], "item_photo": current["item_photo"]}]};
newObj.clause.push(subObj);
}
}
这里是newObj的价值。
{
"clause": [{
"cls": {
"clause_id": 1,
"clause_text": "A"
},
"items": [{
"claud_item_id": 1,
"item_text": "this text is related to clause 1 ",
"item_photo": ""
}]
}, {
"cls": {
"clause_id": 2,
"clause_text": "B"
},
"items": [{
"claud_item_id": 2,
"item_text": "this text is related to clause 2 ",
"item_photo": ""
}, {
"claud_item_id": 3,
"item_text": "this text is related to clause 2",
"item_photo": ""
}, {
"claud_item_id": 4,
"item_text": "this text is related to clause 2",
"item_photo": ""
}]
}, {
"cls": {
"clause_id": 3,
"clause_text": "C"
},
"items": [{
"claud_item_id": 5,
"item_text": "this text is related to clause 3",
"item_photo": ""
}, {
"claud_item_id": 6,
"item_text": "this text is related to clause 3",
"item_photo": ""
}, {
"claud_item_id": 7,
"item_text": "this text is related to clause 3",
"item_photo": ""
}]
}]
}