Question

免责声明：我最近接管了其他人的代码库，因此您在此处看到的部分代码已经预先制作好了。我还将某些变量名称更改为可能无法实际工作的更通用的代码名称。

我正在尝试使用SQLAlchemy在postgres数据库上批量upsert但是遇到了麻烦。似乎当SQLAlchemy访问数据时，它需要更新表（excluded.columnName）它无法找到。

首先是我得到的错误：

    Missing FROM-clause entry for table "excluded"
    LINE 1: ...tablename) VALUES (excluded.tablename...

我的代码：

    index_fields = list(billocity_db.get_indexes(self.table_name))
    for row in self.data:
        if 'id' in self.column_info.keys():
            del row['id']
        data = row.to_dict()
        insert_stmt = insert(self.table).values(data)
        for i in index_fields:
            if i in data:
                del data[i]
        for key in data.keys():
            data[key] = insert_stmt.excluded[key]
            print(data[key])
        print(data)
        insert_stmt = insert_stmt.on_conflict_do_update(
            #Tried both constraint and index_elements with same result
            #constraint=self.table_name,
            #None of my columns are 'id'. Could that be an issue?
            index_elements=['id'],
            set_=data
        )
        try:
            print(insert_stmt)
            self.session.execute(insert_stmt)
        except Exception as e:
            self.session.rollback()
            self.log.exception(str(e))
        finally:
            self.session.commit()

调用

后立即出现错误

self.session.execute(insert_stmt)

这就是insert_stmt在执行之前正确打印的内容，显然column_name和table_name只是占位符。

 INSERT INTO
 table_name (column_name, column_name, column_name, 
 column_name, column_name, column_name, column_name, 
 column_name, column_name, column_name, column_name, 
 column_name, column_name, column_name, column_name, 
 column_name) 
 VALUES
    (
 excluded.column_name, excluded.column_name, excluded.column_name, 
 excluded.column_name, excluded.column_name, excluded.column_name, 
 excluded.column_name, excluded.column_name, excluded.column_name, 
 excluded.column_name, excluded.column_name, excluded.column_name, 
 excluded.column_name, excluded.column_name, excluded.column_name, 
 excluded.column_name
 )
 ON CONFLICT (id) DO 
 UPDATE SET
 column_name= excluded.column_name, column_name= excluded.column_name, 
 column_name= excluded.column_name, column_name= excluded.column_name, 
 column_name= excluded.column_name, column_name= excluded.column_name, 
 column_name= excluded.column_name, column_name= excluded.column_name, 
 column_name= excluded.column_name, column_name= excluded.column_name, 
 column_name= excluded.column_name, column_name= excluded.column_name, 
 column_name= excluded.column_name, column_name= excluded.column_name, 
 column_name= excluded.column_name, column_name= excluded.column_name 
 RETURNING 
 table_name.id

我无法在线找到有关此问题的额外资源，我不知道还有什么可以尝试。任何帮助将不胜感激。

Answer 1

EXCLUDED位于UPDATE部分，但不在VALUES部分。

这是a good tutorial about UPSERT

总是有INSERT ON CONFLICT

的官方文档

SQLAlchemy Upsert无法找到表＆＃34;排除＆＃34;

1 个答案: