我正在尝试创建一个循环,它接受用户的输入并绘制多个正方形,但它会增加每个循环的正方形的大小,但是2个边保持连接。我将包含图片以便更好地解释。
import turtle
squares = 1
while squares >= 1:
squares = int(input('How many squares would you like drawn?:'))
if squares == 0:
print("You must have at-least 1 square.")
squares = int(input('How many squares would you like drawn?:'))
else:
for count in range(squares):
turtle.forward(30)
turtle.left(90)
turtle.forward(30)
turtle.left(90)
turtle.forward(30)
turtle.left(90)
turtle.forward(30)
turtle.left(90)
turtle.done()
答案 0 :(得分:0)
输入请求和绘图逻辑应该分开 这是一种方法,在增加边长后,在每个回合开始时返回乌龟。
import turtle
num_squares = 3
t = turtle.Turtle()
t.pendown()
side = side_unit = 30
while True:
try:
num_squares = int(input('input the number of squares'))
except ValueError:
print("please enter an integer")
if num_squares > 3:
break
for sq in range(1, num_squares + 1):
t.left(90)
t.forward(side)
t.left(90)
t.forward(side)
t.left(90)
t.forward(side)
t.left(90)
side = side_unit + 3 * sq # increase the size of the side
t.goto(0,0) # return to base
turtle.done()
答案 1 :(得分:0)
在等待@ ReblochonMasque的解决方案完成 绘图 100平方时,有足够的时间来实施基于的替代,更快的解决方案的 冲压 强>
首先要注意的是,在提供的说明中,它描绘了绘制100个方格以在图中创建设计,但该图形由不到50个方格组成。它也以一些非整体的方式缩放,使其看起来具有不同的线条厚度。
让我们专注于问题的范围,而不是示例。 OP的最小值为1平方,所以我保留了它。这种解决方案也自然倾向于将正方形置于窗口中心:
from turtle import Turtle, Screen
DELTA = 3
MINIMUM = DELTA * 2
CURSOR_SIZE = 20
num_squares = -1
while num_squares < 1:
try:
num_squares = int(input('Input the number of squares: '))
except ValueError:
print("please enter an integer.")
if num_squares < 1:
print("You must have at least 1 square.")
screen = Screen()
turtle = Turtle("square", visible=False)
turtle.fillcolor("white")
for size in range(((num_squares - 1) * DELTA) + MINIMUM, MINIMUM - 1, -DELTA):
turtle.goto(turtle.xcor() + DELTA/2, turtle.ycor() - DELTA/2)
turtle.shapesize(size / CURSOR_SIZE)
turtle.stamp()
screen.exitonclick()
这显然不是OP所寻求的那种解决方案,但也许下次这样的问题出现时,它可能是OP至少会考虑的问题。