Question

我正在使用Groovy在ready api中实现一个项目。我创建了一个具有以下结构的Groovy脚本文件。

evetS

我需要从json获取节点值，然后从json中删除特定节点。

Answer 1

您不需要顶部的JsonOutput.toJson

试试这个：

def templateValue = '''
{
  "generationTime": null,
  "house": {

    "property": "$property",
    "state": "$state",
    "county": "$county",
    "calls": [
      {
        "first": "$first",
        "second": "$second",
        "third": "third Week"
      }
    ],
    "action": "$action"
  }
}'''
def binding = ["property" : "Villa", "state" : "MA", "county" : "MIDDLE", "first" : "123", "second" : "4565", "action" : "Update"]
def engine = new groovy.text.SimpleTemplateEngine()
def template = engine.createTemplate(templateValue).make(binding)

def jsonSlurper = new groovy.json.JsonSlurper()
Map expectedOutput = jsonSlurper.parseText(template.toString())
println expectedOutput.house.property

Groovy中从String到Map的groovycastexception

1 个答案: