我使用以下代码将一组存储在我的数据库中的文件放入zip文件中:
SqlDataAdapter adp = new SqlDataAdapter("select FILE_NAME, FILE, content_type from tbl where id = " + "168", Configuration.getSQLConnString("ConnStr"));
DataTable dtFiles = new DataTable();
adp.Fill(dtFiles);
if (dtFiles.Rows.Count > 0)
{
using (var zipStream = new ZipOutputStream(Response.OutputStream))
{
foreach (DataRow dr in dtFiles.Rows)
{
byte[] bytes;
string fileName, contentType;
fileName = dr["File_Name"].ToString();
bytes = (byte[])dr["File"];
contentType = dr["Content_Type"].ToString();
Response.Clear();
Response.Buffer = true;
Response.Charset = "";
Response.Cache.SetCacheability(HttpCacheability.NoCache);
Response.AddHeader("Content-Disposition", "attachment; filename=Files.zip");
Response.ContentType = "application/zip";
byte[] fileBytes = bytes;
ZipEntry fileEntry = new ZipEntry(ZipEntry.CleanName(fileName));
fileEntry.Size = fileBytes.Length;
zipStream.SetLevel(3);
zipStream.PutNextEntry(fileEntry);
zipStream.Write(fileBytes, 0, fileBytes.Length);
zipStream.CloseEntry();
}
zipStream.Flush();
zipStream.Close();
}
}
生成并下载了zip文件,它还显示了大约2Mb的大小,但是当我解压缩zip文件时,它显示以下错误:
答案 0 :(得分:0)
ZipOutputStream
根本没有帮助我;试图打破我的头,但没有任何帮助。然后我遇到了这个名为DotNetZip
的库,这里是将存储在数据库中的文件下载到zip文件中的代码:
using (ZipFile zip = new ZipFile())
{
foreach (DataRow dr in dtResumes.Rows)
{
zip.AddEntry(dr["File_Name"].ToString(), (byte[])dr["Resume"]);
}
zip.Save("C:\\Test\\MyZipFile.zip");
}