SELECT Rec.[Reg_ID]
,Rec.[Reg_No]
,Rec.[Case_ID]
,Det.Deleted AS CaseDeleted
,[Status].[Status]
,Det.[Unit_Submission_Date] AS [Signature]
,TD.TargetDate AS [Target]
,TD.TargetID
FROM [dbo].[Regestrations] Rec
LEFT JOIN [dbo].[Reg_Details] Det ON Rec.Case_ID = Det.CaseID
LEFT JOIN [dbo].[lkpStatus] [Status] ON Rec.Status_ID = [Status].StatusID
LEFT JOIN TargetDate TD ON TD.RecommId = Rec.Reg_ID
WHERE (Det.MissionID = 50 AND [Status].[Status] = 1 AND Rec.Deleted = 0 AND Det.Deleted = 0)
GROUP BY Rec.[Reg_ID],Rec.[Reg_No],Rec.[Case_ID]
,[Status].[Status]
,Det.[Unit_Submission_Date]
,TD.TargetDate
,Det.Deleted
,TD.TargetID
ORDER BY TD.TargetID desc
我有上面的查询应该返回唯一Rec.[Reg_No]
的行。但是联接表格TargetDate
可能会有重复的Rec.[Reg_ID]
,如果是这样,我的结果中会出现重复的Rec.[Reg_No]
行。
表TargetDate
有一个日期时间列,因此我想通过从表Rec.[Reg_No]
中选择包含最新日期值的1行来消除重复的TargetDate
。
如何修改我的Join条件或查询where子句以实现上述目的?
答案 0 :(得分:2)
一种方法是使用诸如ROW_NUMBER()
之类的窗口函数,它将根据指定的分区生成序列号。然后可以使用此生成的数字来获取最新的行。
SELECT Reg_ID, Reg_No, Case_ID, CaseDeleted, [Status], Signature, [Target], TargetID
FROM
(
SELECT Rec.[Reg_ID]
,Rec.[Reg_No]
,Rec.[Case_ID]
,Det.Deleted AS CaseDeleted
,[Status].[Status]
,Det.[Unit_Submission_Date] AS [Signature]
,TD.TargetDate AS [Target]
,TD.TargetID
,RN = ROW_NUMBER() OVER (PARTITION BY Rec.[Reg_No] ORDER BY TD.TargetID DESC)
FROM [BOI].[dbo].[Regestrations] Rec
LEFT JOIN [dbo].[Reg_Details] Det ON Rec.Case_ID = Det.CaseID
LEFT JOIN [dbo].[lkpStatus] [Status] ON Rec.Status_ID = [Status].StatusID
LEFT JOIN TargetDate TD ON TD.RecommId = Rec.Reg_ID
WHERE (Det.MissionID = 50 AND [Status].[Status] = 1 AND Rec.Deleted = 0 AND Det.Deleted = 0)
) subQuery
WHERE RN = 1
ORDER BY TargetID desc
答案 1 :(得分:1)
如果您从TD.TargetDate
子句中删除GROUP BY
并计算输出中真正需要的内容,此查询可以正常运行 - MAX(TD.TargetDate)
但最好是避免GROUP BY
条款:
...
FROM [BOI].[dbo].[Regestrations] Rec
LEFT JOIN [dbo].[Reg_Details] Det ON Rec.Case_ID = Det.CaseID
LEFT JOIN [dbo].[lkpStatus] [Status] ON Rec.Status_ID = [Status].StatusID
OUTER APPLY(
SELECT TOP 1 td.TargetDate, td.TargetID
FROM TargetDate TD
WHERE TD.RecommId = Rec.Reg_ID
ORDER BY TD.TargetDate DESC
) td
...
答案 2 :(得分:0)
您应首先为每个RecommId
或RecommId
找到最新的TargetDate。然后,您可以使用与TargetDate表的常规联接,同时匹配TargetDate
和SELECT Rec.[Reg_ID]
,Rec.[Reg_No]
,Rec.[Case_ID]
,Det.Deleted AS CaseDeleted
,[Status].[Status]
,Det.[Unit_Submission_Date] AS [Signature]
,TD.TargetDate AS [Target]
,TD.TargetID
FROM [BOI].[dbo].[Regestrations] Rec
LEFT JOIN [dbo].[Reg_Details] Det ON Rec.Case_ID = Det.CaseID
LEFT JOIN [dbo].[lkpStatus] [Status] ON Rec.Status_ID = [Status].StatusID
LEFT JOIN (SELECT RecommId, MAX(TargetDate) MaxTargetDate GROUP BY RecommId) TDWithLatestDate ON TDWithLatestDate.RecommId = Rec.Reg_ID
LEFT OUTER JOIN TargetDate ON TD.RecommId = TDWithLatestDate.RecommId AND TD.TargetDate = TDWithLatestDate.MaxTargetDate
WHERE (Det.MissionID = 50
AND [Status].[Status] = 1
AND Rec.Deleted = 0
AND Det.Deleted = 0
)
GROUP BY Rec.[Reg_ID]
,Rec.[Reg_No]
,Rec.[Case_ID]
,[Status].[Status]
,Det.[Unit_Submission_Date]
,TD.TargetDate
,Det.Deleted
,TD.TargetID
ORDER BY TD.TargetID desc
。
尝试此查询:
int tcflow(int fildes, int action);
如果您希望在多个记录争用最新时避免平局,则可以改进此查询。