Question

我正试图从我的okg pkg拨打一份宁静的服务;有时使用相同的代码，成功到达此服务并返回响应;但是当网址中的邮件变得更长时==＆gt; ORA-29273 http请求和ORA-29263 http协议被抛出;我不会在通话之间改变任何内容，只会从此网址发送消息;以下是我的程序：

PROCEDURE SEND_SMS(username   VARCHAR2,
                   password   VARCHAR2,
                   phone      VARCHAR2,
                   message    VARCHAR2,
                   code       VARCHAR2,                 
                   P_RESPONSE OUT VARCHAR2) AS

    v_request         UTL_HTTP.req;
    v_response        UTL_HTTP.resp;
    v_text            VARCHAR2(1024);
    v_url             VARCHAR2(1024);
    v_message         VARCHAR2(1024);


  BEGIN
    BEGIN

      P_RESPONSE := '';
      v_message  := REPLACE(message,' ', '%20');


      v_url             := 'http://myservicelink.com/SendSMS?strUsername=' |
                           username || '&strPassword=' || password ||
                           '&strPhone=' || phone || '&strcode=' || code ||
                           '&strMessage=' || v_message;
      v_request         := UTL_HTTP.begin_request(v_url);

      DBMS_OUTPUT.put_line(v_url);

      v_response := UTL_HTTP.get_response(v_request);

      LOOP
        BEGIN
          UTL_HTTP.read_text(v_response, v_text);
          DBMS_OUTPUT.put_line(v_text);
        EXCEPTION
          WHEN UTL_HTTP.end_of_body THEN
            NULL;
        END;

        EXIT WHEN v_text IS NULL;
      END LOOP;

      UTL_HTTP.end_response(v_response);

      IF v_response.status_code <> 200 THEN
        P_RESPONSE := v_response.reason_phrase;
      END IF;

    EXCEPTION
      WHEN OTHERS THEN
       P_RESPONSE := 'An error has occured: ' || SQLERRM;
    END;

  END SEND_SMS;

因此，当v_message变长时，抛出异常。可能是什么错误;请注意，从具有相同输入的ORA pkg外部调用相同的链接 - ＆gt;达到了myservice;

以下是我工作讯息的模板： Dear X, you have been registered to our app. You can download the app for iPhone at link of app store or for android at link of

不工作： Dear X, you have been registered to our app. You can download the app for iPhone at link of app store or for android at link of play store your

Answer 1

你的两个字符串之间的区别不仅仅是长度;第二个也有一个换行符。您正在使用以下内容替换空格：

v_message  := REPLACE(message,' ', '%20');

但这不会与任何其他非法角色打交道。

如果您将其更改为使用the utl_url.escape() function：

v_message  := utl_url.escape(message);

然后它也将转义新行，所以你最后得到第一条消息（与当前代码相同）：

Dear%20X,%20you%20have%20been%20registered%20to%20our%20app.%20You%20can%20download%20the%20app%20for%20iPhone%20at%20link%20of%20app%20store%20or%20for%20android%20at%20link%20of

但这是第二次：

Dear%20X,%20you%20have%20been%20registered%20to%20our%20app.%20You%20can%20download%20the%20app%20for%20iPhone%20at%20link%20of%20app%20store%20or%20for%20android%20at%20link%20of%20play%20store%0Ayour

换行符已编码为%0A。根据消息中的其他内容，您可能需要将true作为第二个参数传递，而不是将其默认为false;差异在上面的文档链接中解释。

仅当URL变为LONG时，ORA-29263才会抛出错误

1 个答案: