Question

我真的很喜欢vanilla JavaScript，所以请耐心等待。

所以我有一个对象数组，如下所示：

var partyGuests =[
    {
        firstName: "Wayne",
        lastName: "Gretzky",
        items: "birthday cake"
    },
    {
        firstName: "Emily",
        lastName: "Janeson",
        items: "balloons"
    },
    {
        firstName: "Gordon",
        lastName: "Ramsey",
        items: "balloons"
    },
    {
        firstName: "Jasmine",
        lastName: "Quaker",
        items: "birthday cake"
    }
]

如果他们带来“气球”，他们会被附加到<div id="balloonGroup">，如果他们带来“生日蛋糕”，他们会被附加到<div id="cakeGroup">

我希望我的整个对象数组显示在页面上（包括姓名，姓氏和项目），但是根据他们带来的项目显示在div中。

我尝试过使用map，forEach和filter，但我不确定我做错了什么。

这是我尝试过的，但我无法找到一种方法将它们分类到适当的div中。

let guests = partyGuests.map(res=>{
    return res;
})

function groupAssignment(value, index){
    const FirstName = `<li>Name: ${value.firstName}</li>`;
    const LastName = `<li> Last Name: ${value.lastName}</li>`;
    const Item = `<li>Item: ${value.item}</li>`;
    $("#1").append(firstName, lastName, Item);
}

guests.forEach(groupAssignment);

Answer 1

您只需循环遍历数组并填充div分别具有id的内容：

＆＃13;

var partyGuests =[
    {
        firstName: "Wayne",
        lastName: "Gretzky",
        items: "birthday cake"
    },
    {
        firstName: "Emily",
        lastName: "Janeson",
        items: "balloons"
    },
    {
        firstName: "Gordon",
        lastName: "Ramsey",
        items: "balloons"
    },
    {
        firstName: "Jasmine",
        lastName: "Quaker",
        items: "birthday cake"
    }
];
partyGuests.forEach((obj)=>{
  if(obj.items === 'balloons'){
    $('#balloonGroup').append(
      obj.firstName + ' ' + obj.lastName + ' '
      + obj.items + '<br>'
    );
  }
  
  if(obj.items === 'birthday cake'){
   $('#cakeGroup').append(
       obj.firstName + ' ' + obj.lastName + ' '
       + obj.items + '<br>'
    );
  }
});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="balloonGroup"></div>
<div id="cakeGroup"></div>

＆＃13;

Answer 2

您应该在代码中使用.forEach，因为您只需迭代所有数组元素。

这里采取的步骤是：

迭代数组元素。
构建要追加的HTML字符串。
根据items值获取要添加的选择器。
使用.append()

＆＃13;

var partyGuests = [{
    firstName: "Wayne",
    lastName: "Gretzky",
    items: "birthday cake"
  },
  {
    firstName: "Emily",
    lastName: "Janeson",
    items: "balloons"
  },
  {
    firstName: "Gordon",
    lastName: "Ramsey",
    items: "balloons"
  },
  {
    firstName: "Jasmine",
    lastName: "Quaker",
    items: "birthday cake"
  }
];

partyGuests.forEach(
  el => {
    var _html = '<p><strong>First Name:</strong>' + el.firstName + '<br>' +
      '<strong>Last Name:</strong>' + el.lastName + '<br>' +
      '<strong>Items:</strong>' + el.items + '<br></p>';

    var elem = "";
    if (el.items === "birthday cake")
      elem = '#cakeGroup';
    else if (el.items === "balloons")
      elem = '#balloonGroup';

    $(elem).append(_html);

  }
)

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="balloonGroup">
  <h3>Balloons</h3>
</div>

<div id="cakeGroup">
  <h3>Cakes</h3>
</div>

＆＃13;

Answer 3

for(var i=0; i<partyGuests.length; i++){
  if (partyGuests[i].items == "birthday cake") {
   //append to cakeGroup here 
  } else if (partyGuests[i].items == "balloons") {
   //append to balloonGroup
  }
}

遍历guest虚拟机数组并检查items属性

如何基于其键值对JavaScript对对象进行排序和显示

3 个答案: