Question

两张桌子 - '薪水'和'master1'

薪水是按年计算的，我可以将它们分组，以便使用

获得每位玩家的总和

SELECT playerID, sum(salary) as sal 
FROM salaries 
GROUP BY playerID ORDER BY sal DESC LIMIT 10;

这将返回playerID和工资总和，但我需要'name1'和'nameLast'列下'master1'表中的玩家姓名。他们在'master1'和'薪水'中都有'playerID'的公共列，但是当我尝试运行时

SELECT master1.nameFirst, master1.nameLast, sum(salary) as sal 
FROM salaries, master1 
GROUP BY salaries.playerID ORDER BY sal DESC LIMIT 10;

我收到错误表达式不在GROUP BY键'nameFirst'

中

我尝试过修补它以继续收到错误。

谢谢！

Answer 1

需要在nameFirst中包含nameLast和group by：

SELECT 
master1.nameFirst, 
master1.nameLast, 
sum(salary) as sal 
FROM salaries JOIN master1 ON salaries.playID = master1.playerID
GROUP BY master1.nameFirst, master1.nameLast, salaries.playerID 
ORDER BY sal DESC LIMIT 10;

Answer 2

首先，您需要使用正确的显式JOIN语法

SELECT  
        MAX(m.nameFirst) FirstName,
        MAX(m.nameLast) LastName,
        SUM(s.salary) Salary
FROM master1 m
INNER JOIN salaries s ON m.playerID = s.playerID 
GROUP BY m.playerID

使用master1表获取 FirstName ， LastName ，然后执行JOIN salaries表来获取每个玩家的总薪水。

对于使用GROUP BY子句时的当前查询异常，请确保SELECT语句中的 columns / expressions 需要聚合。

多表中的HIVE组

2 个答案: