如何通过JOptionPane进行简单的循环

Question

我很新，找不到我想要的确切答案。我试图使用JOptionPane创建一个非常简单的循环，其中我插入1-10之间的值并保持循环它。如果值超过10或低于1，您应该要求用户再试一次。到目前为止，我有这个。如果值达到0，则程序应该结束。

    String ans_s = JOptionPane.showInputDialog( "Please enter a rating between 1-10 (0 to stop)");
    int number = Integer.parseInt(ans_s);
    if (number > 10 || number < 0) {
    JOptionPane.showMessageDialog( null, "Please Try Again");
    ans_s = JOptionPane.showInputDialog( "Please enter a number between 1-10 (0 to stop)");
    number = Integer.parseInt(ans_s);
    }
    else if (number < 10 || number > 0) {
    ans_s = JOptionPane.showInputDialog( "Please enter a rating between 1-10 (0 to stop)");

    }
    else if (number == 0) {

     JOptionPane.showMessageDialog(null, "Finished");
    }

似乎没有什么循环所以我只需要一些指导。谢谢

Answer 1

你需要一个循环结构，

boolean control_statement = true;
while (control_statement) {
    codeInThisMethodWillLoop(); //Until control_statement = false
}

或

final int maxLoops = 10; //can be any number
for (int loopCounter = 0; loopCounter < maxLoops; loopCounter++) {
    codeInThisMethodWillLoop(); //Until loopCounter = maxLoops
}

在你的情况下

int number = -1;
while (number != 0) {
    String ans_s = JOptionPane.showInputDialog( "Please enter a rating between 1-10 (0 to stop)");
    number = Integer.parseInt(ans_s);
    if (number > 10 || number < 0) {
        JOptionPane.showMessageDialog( null, "Please Try Again");
        ans_s = JOptionPane.showInputDialog( "Please enter a number between 1-10 (0 to stop)");
        number = Integer.parseInt(ans_s);
    }
    else if (number < 10 || number > 0) {
        ans_s = JOptionPane.showInputDialog( "Please enter a rating between 1-10 (0 to stop)");
    }
    else if (number == 0) {
         JOptionPane.showMessageDialog(null, "Finished");
    }
}