我的桌子看起来像这样:
df <- data.frame(week = c("one","one","two","two"),
Day = c("day1", "day2","day1","day2"),
daily_freq = c(100,110,90,90),
city1 = c(20,30,20,30),
city2 = c(10,20,30,40),
city3 = c(30,40,10,10),
city4 = c(40,20,30,10))
我正在计算几个汇总表,例如,一个表中包含该期间的总频率:
resume_table <- setDT(df)[, .( total_freq = sum(daily_freq),
city1 = sum(city1),
city2 = sum(city2),
city3 = sum(city3),
city4 = sum(city4))
,by = .(week)]
查找总频率如下所示的表格:
week total_freq city1 city2 city3 city4
one 210 50 30 70 60
two 180 50 70 20 40
但是因为我有几个城市(超过40个),而且我需要计算几个汇总表,所以我希望有一个带有城市的向量:
cities <- c("city1","city2","city3","city4")
并且每次我对这个向量变量进行求和并且仍然对其他列求和时,能够调用此向量。 我的代码不起作用:
resume_table2 <- setDT(df)[, .(total_freq = sum(daily_freq),
lapply(.SD, sum), .SDcols = cities)
,by = .(week)]
出了什么问题?
答案 0 :(得分:0)
我们可以指定&#39;城市&#39;向量.SDcols
中的向量并在.SD
上方循环以获取sum
setDT(df)[, lapply(.SD, sum), .SDcols = cities]
# city1 city2 city3 city4
#1: 105 100 55 65
如果我们需要&#39; daily_freq&#39;同时,再与“城市”联系起来
setDT(df)[, lapply(.SD, sum), .SDcols = c('daily_freq', cities)]
# daily_freq city1 city2 city3 city4
#1: 325 105 100 55 65