Question

我有以下python的整数字典：

{1: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15],
 2: [3, 6, 13],
 3: [1, 2, 3],
 4: [13, 14, 15],
 5: [3, 6],
 6: [6, 13]}

我想将第5和第6个条目中的数字6删除到字典中。我知道这很简单，但我是python的新手所以所有人都很感激。谢谢。

Answer 1

像你想象的那样直截了当：

dct = {1: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15],
 2: [3, 6, 13],
 3: [1, 2, 3],
 4: [13, 14, 15],
 5: [3, 6],
 6: [6, 13]}

dct[5].remove(6)
dct[6].remove(6)

print(dct)

由于list为mutable sequence types，因此他们使用.remove(element)方法。

Answer 2

您可以为此定义一个功能。给定字典d：

def remover(d, keys, value):
    for k in keys:
        d[k].remove(value)
    return d

remover(d, [5, 6], 6)

# {1: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15],
#  2: [3, 6, 13],
#  3: [1, 2, 3],
#  4: [13, 14, 15],
#  5: [3],
#  6: [13]}

Answer 3

在每个条目上使用list.remove：

my_dict[5].remove(6)
my_dict[6].remove(6)

Answer 4

您还可以使用列表推导删除值：

>>> d = {1: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15],2: [3, 6, 
13],3: [1, 2, 3],4: [13, 14, 15],5: [3, 6],6: [6, 13]}
>>> d[5] = [x for x in d[5] if x != 6]
>>> d[6] = [x for x in d[6] if x != 6]
>>> d 
{1: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15], 2: [3, 6, 13], 3: [1, 2, 3], 4: [13, 14, 15], 5: [3], 6: [13]}

Python从字典中删除特定值

4 个答案: