在Javascript中使用setter方法时未被捕获的引用错误

Question

let person = {
  _name: 'Lu Xun',
  _age: 137,

  set age(ageIn) {
    if (typeof ageIn === 'number') {
      this._age = ageIn;
    }
    else {
      console.log('Invalid input');
      return 'Invalid input';
    }
  }

};
console.log(person.set age('bdhh'));

//执行代码时会将错误视为未捕获的引用    错误

Answer 1

你以错误的方式调用setter。

person.age = 15; // this is how you call your setter

在jsFiddle中查看您的更新代码：https://jsfiddle.net/t3uzpobn/4/

Answer 2

调用setter的方式不正确：

let person = {
  _name: 'Lu Xun',
  _age: 137,

  set age(ageIn) {
    if (typeof ageIn === 'number') {
      this._age = ageIn;
    }
    else {
      console.log('Invalid input');
      return 'Invalid input';
    }
  }

};
console.log(person.age = 'bdhh');
console.log(person.age = 13);

Answer 3

您的通话方法不正确

let person = {
  _name: 'Lu Xun',
  _age: 137,

  set age(ageIn) {
    if (typeof ageIn === 'number') {
      this._age = ageIn;
    }
    else {
      console.log('Invalid input');
      return 'Invalid input';
    }
  }

};
console.log(person.age = 'bdhh');