Question

我正在尝试按第8列排序列表（拆分文件后）但是我一直收到此错误：

ValueError: invalid literal for int() with base 10: '72912,'

这是我正在尝试排序的列表：

UDP outside 192.168.30.33:1046 inside 192.168.84.28:161, idle 0:00:18, bytes 72912, flags  
TCP outside 192.168.120.26:1339 inside 192.168.84.17:445, idle 5:29:24, bytes 19305, flags  
TCP outside 192.168.120.26:1271 inside 192.168.84.161:139, idle 5:29:41, bytes 4346, flags  
TCP outside 192.168.120.60:1955 inside 192.168.84.100:445, idle 3:56:40, bytes 259388, flags  
TCP outside 192.168.120.60:1951 inside 192.168.84.17:445, idle 3:56:40, bytes 257120, flags   
TCP outside 192.168.120.60:1940 inside 192.168.84.161:139, idle 3:56:57, bytes 260372, flags  
TCP outside 192.168.120.49:1324 inside 192.168.84.161:445, idle 5:04:12, bytes 2705, flags

这是我的Python脚本：

lines = open("home/file.txt", "r").readlines() 
lines = [x.split() for x in lines] 
lines.sort(cmp, key=lambda x:int(x[8]), reverse=True) 
for i in lines: 
    print i

任何帮助都非常感谢...

Answer 1

在尝试将其转换为整数之前，您需要删除列中的尾随逗号。

lines.sort(cmp, key=lambda x:int(x[8][:-1]), reverse=True)

这有所不同。

In [1]: foo = '72912,'
In [2]: int(foo)
ValueError: invalid literal for int() with base 10: '72912,'

In [3]: int(foo[:-1])
Out[3]: 72912

Answer 2

您尝试转换为int的数字为'，'。所以，在你的代码而不是

lines.sort(cmp, key=lambda x:int(x[8]), reverse=True)

试

lines.sort(cmp, key=lambda x:int(x[8].strip(',')), reverse=True)

尝试对整数进行排序，但得到'带有基数10'的int（）的无效文字错误

2 个答案: