TTS - 角色扮演

Question

构建TTS应用程序

App正在从SQLite上滑动显示单词 并立即说话

但是如果用户快速刷两次或三次跳过单词，它仍然会说旧的（即第一个单词）

发言

public void speak(){
    text = txt_word.getText().toString();
    final char[] chars = text.toCharArray();
    Toast.makeText(this, String.valueOf(chars.length), Toast.LENGTH_SHORT).show();
    textToSpeech.setPitch((float) 0.80);

    final boolean[] stop = {false};

    final int delay = 700;
    final int[] i = {0};
    final Handler handler=  new Handler();
    handler.postDelayed(new Runnable() {
        @Override
        public void run() {
            if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP) {
                textToSpeech.speak(String.valueOf(chars[i[0]]),TextToSpeech.QUEUE_FLUSH,null,null);
            } else {
                textToSpeech.speak(String.valueOf(chars[i[0]]), TextToSpeech.QUEUE_FLUSH, null);
            }

            i[0]++;
            if(i[0]>=chars.length){
                stop[0] =true;

            }
            //do your work here..

            if (!stop[0]) {
                handler.postDelayed(this, delay);
            }
        }
    }, delay);
    textToSpeech.speak(text,TextToSpeech.QUEUE_FLUSH,null);
    //Toast.makeText(this,text , Toast.LENGTH_SHORT).show();
}

SWIPE CALL

public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX, float velocityY) {
    if (e1.getX() > e2.getX()) {
        Cursor c = db.random();
        c.moveToFirst();
        txt_word.setText(c.getString(c.getColumnIndex("word")));
        speak();
    }