Question

正在尝试金字塔网站中的快速入门指南：https://trypyramid.com

from wsgiref.simple_server import make_server
from pyramid.config import Configurator
from pyramid.request import Response

def hello_world(request):
    return Response('Hello World')

if __name__ == "__main__":
    with Configurator() as config:
        config.add_route('hello','/')
        config.add_view(hello_world, route_name='hello')
        app = config.make_wsgi_app()

    server = make_server('0.0.0.0',6543,app)

给出以下错误：

/anaconda3/bin/python /Users/user1/Desktop/play/pyramid_play/tut_1/exp1.py
Traceback (most recent call last):
  File "/Users/user1/Desktop/play/pyramid_play/tut_1/exp1.py", line 12, in <module>
    with Configurator() as config:
AttributeError: __enter__

Process finished with exit code 1

Answer 1

谢谢Steve Piercy。这是一个安装问题。我让pycharm在创建项目时安装Pyramid。 pycharm使用conda来安装包，它安装了v1.5.7（最新的conda repos）而不是1.9.1（当前版本）。我安装了pip来安装修复问题的最新版本。

pyramid.config.Configurator（）不能与'with'上下文管理器一起使用

1 个答案: