Question

一位朋友给了我一个想法，写一个程序，询问你英语单词，你必须用德语和反向翻译它们。

因此程序会询问一个单词并检查输入是否与实际翻译匹配。

因此，用户输入他/她想要学习的单元。此输入存储在变量中。现在我有一个单元1的单词列表。然后程序随机选择列表中的单词。然后打印该单词并且用户输入他的答案。然后使用.index我找到所述单词的位置并在第二个列表中搜索相同的位置。

我的问题是单位输入被视为字符串而不是我所制作的列表之一。因此，用户只需要从此输入中获取信件。

我想以某种方式让这个输入等于我拥有和工作的列表的名称。（列表实际上更大，我剪切它们使它更容易阅读）

代码在这里：

import random

U1_E = ["consider (sb) to be …","describe (sb) as ...","proud to + infinitive"
    ]
U1_D = ["erachten, wähnen","erachten, wähnen","beschreiben"
    ]
U5_E = ["confortable","crowded","delicious","efficient","fashionable",
    ]                                                      
U5_D = ["bequem","überfüllt","köstlich","effizient","modisch"
    ]                                                       
Num = ["first","second","third","forth","fifth","sixth","7th","8th","9th",
    ]                                                     
Unit_Eng = ["U1_E","U2_E","U3_E","U4_E","U5_E","U6_E","U7_E","U8_E"
    ]                                                       
good_points = 0                                            
bad_points = 0                                              
Name_of_Agent = input("Can you please give me your name?")  
Select_Unit = input(Name_of_Agent + ",which Unit would you like to train?    [Ux_E/Ux_D]")  
Num_of_Words = int(input("How many words would you like?")) 


if (Select_Unit in Unit_Eng):
    for i in range(0,Num_of_Words):                             
        Word_E = random.choice(Select_Unit)                    
        Select_Unit_oposite = Select_Unit[:3] + "D"             
        Word_D = Select_Unit_oposite[Select_Unit.index(Word_E)] 
        if (input("The "+Num[i]+" Word is:"+Word_E+":") == Word_D):      
            print("Well done, you got it right!")               
            good_points = good_points + 1                      
        else:
            print("The word you gave is wrong, the right answer is:",   Word_D)    
            bad_points = bad_points + 1                                       
    print("Your total score is:",good_points-    bad_points)                       


input("Press Enter to close the program")

Answer 1

问题在于您尝试使用Select_Unit作为列表而不是您要访问的列表的名称。

有几种不同的方法可以实现这一点，如果你想进一步提升你的Python知识，你应该尝试不同的方法。

一种让人想起的方法是将单位存储在列表的Python字典中而不是一系列列表中，这样您就可以立即访问单位名称后面的值（单位）已经确认它存在于您的单位中。

它可能类似于以下内容

units = {"unit_1": ["word_1", "word_2", ...], "unit_2": ...}
# get input including the unit they want
if unit in units:
    chosen_unit = units[unit]
    # continue to do whatever you need to extract the information now that you have the chosen unit.

输入应该等于列表，但不是

1 个答案: