列出前一天和周末后一天不在列表中的员工列表

Question

我需要一周前和周末后一天缺席的员工名单......比如周五和周一不在场的员工不应列入名单

Answer 1

使用datepart（工作日）来获取相对于星期一和星期五的所有记录。

也可以查看SET DATEFIRST功能。

select *
from   your_table
where  datepart(weekday, Date) = 5 
or     datepart(weekday, Date) = 1;

Answer 2

这将列出周五和下周一（+1周）缺席的所有员工ID。我从表格的最小日期到最大日期设置了一个日历周，并且仅在周五和周一进行。然后得到所有在任何一个日期都没有出席的empid。

with caldte as (
SELECT  dateadd(day, rn - 1, t.mindte) as dates,
        datepart(weekday, dateadd(day, rn - 1, t.mindte)) as weekday,
        datepart(wk, dateadd(day, rn - 1, t.mindte)) as weeknum
FROM    ( 
  select row_number() OVER ( order by c.object_id ) AS rn
  FROM sys.columns c) rns, 
  (select min(dte) as mindte, max(dte) as maxdte 
   from tbl) t
    WHERE   rn - 1 <= datediff(day, t.mindte, t.maxdte)
    and datepart(weekday, dateadd(day, rn - 1, t.mindte)) in (2, 6)
  )
select distinct empid  
from tbl
where empid not in (
  select t.empid
  from caldte c, tbl t
  where c.dates = t.dte)
order by empid