Question

我想设置我的颤动曲线轴的极限s.t.外部使用的网格中的NaN不会导致我的ax限制在没有任何数据点的情况下不必要地长。

我自己得到的是：

import numpy as np
pylab.xlim(np.min(Km[np.isnan(C_diff) < 0.5 ]), np.max(Km[np.isnan(C_diff) < 0.5 ]))
    #two conditions: "np.min(Cm[np.isnan(K_diff) < 0.5" on min, max (Km) are missing 

pylab.ylim(np.min(Cm[np.isnan(K_diff) < 0.5 ]), np.max(Cm[np.isnan(K_diff) < 0.5 ])) 
    #two conditions: "np.min(Km[np.isnan(K_diff) < 0.5" on min, max (Cm) are missing

为了进一步说明，用matlab语言我想要：

xlim([min(min(Km(real(~(isnan(K_diff))).*real(~(isnan(C_diff))) > 0.5))),
max(max(Km(real(~(isnan(K_diff))).*real(~(isnan(C_diff))) > 0.5)))]);

ylim([min(min(Cm(real(~(isnan(K_diff))).*real(~(isnan(C_diff))) > 0.5))),
max(max(Cm(real(~(isnan(K_diff))).*real(~(isnan(C_diff))) > 0.5)))]);

很高兴得到答案！提前致谢！：）

托拜厄斯

Answer 1

我想我通过以下方式解决了这个问题：

pylab.xlim(np.min(Km[np.isnan(C_diff)^np.isnan(K_diff).all() < 0.5 ]), 
np.max(Km[np.isnan(C_diff)^np.isnan(K_diff).all() < 0.5 ]))
pylab.ylim(np.min(Cm[np.isnan(K_diff)^np.isnan(C_diff).all() < 0.5 ]),
np.max(Cm[np.isnan(K_diff)^np.isnan(C_diff).all() < 0.5 ]))

然而，从结果来看，我认为没有区别，但逻辑运算符可以做到这一点。

Python：如何在我的箭头绘图轴的极限上添加第二个＆＃34;非Nan＆＃34; -condition？

1 个答案: