从下面的散文中,我想从任意一行中提取一个包含字母“HTML”的数字列表。 html可以是大写或小写。
所以这是psuedo代码: text = getline() 如果文本包含html 匹配文本中的任何数字 返回匹配数组
如何在REG Ex中做到这一点?
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答案 0 :(得分:1)
首先检查字符串中是否有html
,然后匹配所有数字:
if (preg_match("/html/i", $input)) {
preg_match_all("/\b(\d+)\b/", $input, $m);
}
print_r($m);
答案 1 :(得分:0)
样本解决方案:
$line=strtolower($line);
$x = preg_match("/html.*(\d+)/",$line,$match) || preg_match("/(\d+).*html/",$line,$match);
if($x)echo "number in line: ".$match[1];
假设只有一个数字。绝对不是最好的方法,但你真的应该自己学习正则表达式 - 这并不难。
答案 2 :(得分:0)
^((\d+)|.)*(HTML|html)((\d+)|.)*$
使捕获组正确可能有点棘手,但只是乱七八糟。