Question

我必须为我的计算机科学课程编写一个简单的程序，我的老师要我用循环和开关打印出十二天的圣诞歌曲，我试图运行这段代码但是开关被跳过了完全。如果你可以帮助我，那将是伟大的，谢谢！

#include <iostream>
using namespace std;
int main()
{
 for (int i = 12; i > 0; i--) 
 {
    cout << "On the " << i << " day of Christmas my true love gave to me, \n";
    switch (i)
    {
        case 1: "Twelve drummers drumming\n";
        case 2: "Eleven pipers piping\n";
        case 3: "Ten lords a-leaping\n";
        case 4: "Nine ladies dancingn";
        case 5: "Eight maids a-milking\n";
        case 6: "Seven swans a-swimming\n";
        case 7: "Six geese a-laying\n";
        case 8: "Five gold rings\n";
        case 9: "Four colly birds\n";
        case 10: "Three french hens\n";
        case 11: "Two turtle doves, and\n";
        case 12: "A partridge in a pear tree\n";
                break;
    }
 }
system("pause");
return 0;
}

Answer 1

我正在尝试运行此代码但是交换机完全被跳过？不会跳过switch，评估switch表达式，但由于没有cout语句，因此不会打印任何内容。

在每种情况下将cout语句添加为

std::cout <<"A partridge in a pear tree"<<std::endl;
break;/* if required */

如果需要，请在每种情况下放置break。

    switch (i)
    {
          case 1: std::cout<<"Twelve drummers drumming"<<std::endl;
                  break; /* if required */
                  /* add remaining case */
    }

C ++完全跳过一个开关

1 个答案: