Question

无法在同一行中设置2个计数。我的查询结果是这样的： enter image description here

我认为最终结果如下： enter image description here 并在最后建立precent count1到count2

我的尝试槽案没有成功：SELECT Date，Shift，CASE description WHEN'Defects'THEN count ELSE 0 END AS Defect_Count，CASE description WHEN'Total'THEN count ELSE 0 END AS Total_Count FROM（“Queries union）< / p>

Answer 1

你走了。希望这可以帮助。感谢。

MYSQL:
select
    t.dates, t.shift,
    sum(case when t.description = 'Defects' then t.counts else 0 end) as `Defects`,
    sum(case when t.description = 'Total' then t.counts else 0 end) as `Total`
from (
    select *
    from tbl ) t
group by t.dates, t.shift
order by t.dates, t.shift

ORACLE:
SELECT dates, shift, defects , total
FROM
(
  SELECT *
  FROM tbl
)  
PIVOT
(
  sum(counts)
  FOR description IN ('Defects' as defects, 'Total' as total)
)  
ORDER BY dates

Result:
dates       shift Defects  Total
2018-01-20  AM      21     56
2018-01-20  PM      19     54
2018-01-23  AM      16     58
2018-01-23  PM      20     45

Answer 2

很多谢谢正在为第一步工作（计入同一行）。

我现在将尝试构建百分比（缺陷为总计）。感谢。

构建百分比（缺陷为总计）： select dates,shift,defects,total,round((100*defects/total),2) Percent2Total from(select t.dates, t.shift, sum(case when t.description = 'Defects' then t.counts else 0 end) as 'Defects', sum(case when t.description = 'total' then t.counts else 0 end) as 'Total' from ( select * from tbl ) t group by t.dates, t.shift )q order by dates,Shift。可能只能用Pivot或？

来构建它

同一行中的两个计数

2 个答案: