Question

我正在尝试拉出一个sting变量并将其放在一个shape函数中，以便显示正确的状态。我有一个（硬编码）版本工作，但我试图通过添加循环使代码高效和更动态。

请参阅以下代码：

PShape usa;

PShape Alabama;
PShape Alaska;
PShape Arizona;
PShape Arkansas;

void setup() {
  size(1000, 1000);  
  usa = loadShape("map.svg");

  Alabama= usa.getChild("AL");
  Alaska= usa.getChild("AK");
  Arizona= usa.getChild("AZ");
  Arkansas= usa.getChild("AR");
}

void draw() {
  background(255);
  Table table = loadTable("data.csv", "header");
  for (int i = 0; i < table.getRowCount(); i++) {

    // Gets the 1st (then 2nd, then 3rd...) TABLE ROW
    TableRow row = table.getRow(i);

    //  Gets the data values and places in variables
    String state = row.getString("state");
    String state_abv = row.getString("state_abv");
    float percentage = row.getFloat("percentage");


    // Draw the full map
    shape(usa, 0, 0);

    //*****************************
    // THIS IS THE DYNAMIC ATTEMPT
    state.disableStyle();
    fill(0);
    shape(state, 0, 0);
    text(state_abv, 100 100);
    text(percentage, 100 150);


    // THIS WORKS BUT IS A SINGLE STATE AND HARD CODE...
    // NewJersey.disableStyle();
    // fill(R, 255, 255);
    // shape(NewJersey, 0, 0);

    // DATA FILE IS LIKE SO:
    // state, state_abv,percentage
    /*
     Alabama,AL,21.5
     Alaska,AK,19
     Arizona,AZ,14.7
     Arkansas,AR,23.6
     */
  }
}

Answer 1

如果我理解你的问题，听起来你正在寻找HashMap课程。与数组如何将索引（0,1,2,3 ......）映射到值类似，HashMap映射任何对象（包括String，如"PA"，{{ 1}}，"VA" ...）到一个值。这是一个基本的例子：

"CA"

此示例将HashMap<String, String> map = new HashMap<String, String>(); map.put("PA", "Harrisburg"); map.put("VA", "Richmond"); map.put("CA", "Sacramento"); String city = map.get("VA"); println(city);键映射到String值，但您可以将任何对象用作键或值。更多信息可以在the reference找到。

如果您仍然无法解决问题，请在新问题中发布MCVE，我们将从那里开始。祝你好运。

Answer 2

这是一个有效的解决方案，虽然FILL COLOR问题仍未解决......（这是一个单独的问题）。但这确实将来自外部数据文件的所有数据放入一个正常运行的数组“states []”

PShape usa;
PShape[] states;       // array to hold all states
int numstates;         //count number of states

void setup() {
  size(1000, 1000);

  //load the map
  usa = loadShape("map.svg");
  parseMap();          
  smooth();
  noLoop();
}

void draw() {
  background(200);
  drawMap();
}

// ***** ------------------------
// ***** ----- PARSE MAP
// ***** ------------------------
void parseMap() {
  numstates = usa.getChildCount(); //count number of child shapes on map
  states = new PShape[numstates];
  //println("NUMSTATES " + numstates);

  // stateCodes = new String[numstates];
  usa.disableStyle(); //turn off styles for whole map

  //make state objects
  for (int i = 0; i < numstates; i++) {
    states[i] = usa.getChild(i);
    println("NUMSTATES " + states[i]);
  }
}


// ***** ------------------------
// ***** ----- DRAW MAP
// ***** ------------------------
void drawMap() {
  for (int n = 0; n < numstates; n++) {

    Table table = loadTable("data.csv", "header");
    for (int i = 0; i < table.getRowCount(); i++) {

      // Gets the 1st (then 2nd, then 3rd...) TABLE ROW
      TableRow row = table.getRow(i);

      //  Gets the data values and places in variables
      String s = row.getString("state");
      String a = row.getString("abv");
      float p = row.getFloat("percent");
      int colora = row.getInt("colora");
      int colorb = row.getInt("colorb");
      int colorc = row.getInt("colorc");
      int loca = row.getInt("loca");
      int locb = row.getInt("locb");

      states[n].disableStyle();
      // fill(colora,colorb,colorc);          // PROBLEM HERE: It fills ALL states same color
      states[n].fill(colora,colorb,colorc);   // I AM TRYING TO FILL EACH STATE A DIFFERNET COLOR
      stroke(255,0,0);
      strokeWeight(2);
      shape(states[n],0,0);
      fill(255);
      text(p, loca, locb);
    }
    println("NUMSTATES " + numstates);
  }
}

进程在循环中用作Pshape的字符串名称

2 个答案: