资源

Question

我有以下json对象，我想显示天气对象描述，当我尝试显示它给出undefined的对象时。任何人都可以告诉我如何访问它？

{
  "coord": {
    "lon": 80.28,
    "lat": 13.09
  },
  "weather": [
    {
      "id": 800,
      "main": "Clear",
      "description": "clear sky",
      "icon": "01n"
    }
  ],
  "base": "stations",
  "main": {
    "temp": 299.15,
    "pressure": 1015,
    "humidity": 74,
    "temp_min": 299.15,
    "temp_max": 299.15
  },
  "visibility": 6000,
  "wind": {
    "speed": 3.1,
    "deg": 60
  },
  "clouds": {
    "all": 0
  },
  "dt": 1519491600,
  "sys": {
    "type": 1,
    "id": 7834,
    "message": 0.0057,
    "country": "IN",
    "sunrise": 1519433836,
    "sunset": 1519476414
  },
  "id": 1264527,
  "name": "Chennai",
  "cod": 200
}

Answer 1

对象weather是一个数组，因此您需要遍历对象。

您可以使用forEach功能。

var obj = {  "coord": {    "lon": 80.28,    "lat": 13.09  },  "weather": [{    "id": 800,    "main": "Clear",    "description": "clear sky",    "icon": "01n"  }],  "base": "stations",  "main": {    "temp": 299.15,    "pressure": 1015,    "humidity": 74,    "temp_min": 299.15,    "temp_max": 299.15  },  "visibility": 6000,  "wind": {    "speed": 3.1,    "deg": 60  },  "clouds": {    "all": 0  },  "dt": 1519491600,  "sys": {    "type": 1,    "id": 7834,    "message": 0.0057,    "country": "IN",    "sunrise": 1519433836,    "sunset": 1519476414  },  "id": 1264527,  "name": "Chennai",  "cod": 200};

obj.weather.forEach(w => console.log(w.description));

.as-console-wrapper { max-height: 100% !important; top: 0; }

资源

Array.prototype.forEach()

Answer 2

只需访问对象的weather属性，该属性只是一个项目（item [0]）的数组，这是另一个对象，然后是该对象的description属性：

var obj = {"coord":{"lon":80.28,"lat":13.09},
"weather":[
        {"id":800,"main":"Clear","description":"clear sky","icon":"01n"}
    ],
"base":"stations",
"main":{"temp":299.15,"pressure":1015,"humidity":74,"temp_min":299.15,"temp_max":299.15},
"visibility":6000,
"wind":{"speed":3.1,"deg":60},
"clouds":{"all":0},"dt":1519491600,
"sys":{"type":1,"id":7834,"message":0.0057,"country":"IN","sunrise":1519433836,"sunset":1519476414},
"id":1264527,"name":"Chennai","cod":200
};

console.log(obj.weather[0].description);

如果您对将要返回的JSON有任何控制权，则weather似乎不需要包含对象的数组。如果总是只有一个对象，那么结构将更有意义：

{"coord":{"lon":80.28,"lat":13.09},
"weather":{"id":800,"main":"Clear","description":"clear sky","icon":"01n"},
...

如何访问json对象中的天气描述

2 个答案:

资源