我正在尝试实现这样的示例：Person类有一个它喜欢的地方列表。但是当我想查询它时，我希望结果为每个人只有最喜欢的地方（只是第一个不是全部）。所以我这样做了：
@Entity
class Person{
...
@ManyToMany(cascade = {CascadeType.REFRESH,CascadeType.PERSIST}, fetch = FetchType.EAGER)
@JoinTable(name = "person_favorite_place",
joinColumns = @JoinColumn(name = "person_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "place_id", referencedColumnName = "id")
)
@OrderColumn(name="favorite_place_order")
List<Place> favoritePlaces;
}
在存储库中，我做了：
public interface PersonRepository extends JpaRepository<Person, Long> {
@Query(value = "select person0_.id as id1_0_0_, person0_.age as age2_0_0_, person0_.name as name3_0_0_, favoriteme1_.person_id as person_id1_1_1_, place2_.id as place_id2_1_1_, favoriteme1_.favorite_place_order as favorite3_1_, place2_.id as id1_3_2_, place2_.invented as invented2_3_2_, place2_.name as name3_3_2_ from person person0_ left outer join person_favorite_place favoriteme1_ on person0_.id=favoriteme1_.person_id left outer join place place2_ on favoriteme1_.place_id=place2_.id where person0_.id=:personId and favoriteme1_.favorite_place_order = 0", nativeQuery = true)
Person getPersonWithFavoritePlace(@Param("personId") Long personId);
}
正如预期的那样，查询需要为每个Person返回1个Place，但它总是返回Person喜欢的所有位置。我在这里做错了什么？