我正在尝试动态添加包含表单
的表格行<tr><form><td>Input type</td><td>Submit Form</td></tr></form>
但我未能得到我的JavaScript文件的确切结果如下:
//adding new row for table in upcoming classes module.
var counter = 0;
$("#addrow").on("click", function () {
var newRow = $("<tr><form id="scheudleTable1">");
var cols = "";
cols += '<td><input type="text" class="form-control" placeholder="Name" name="student_name' + counter + '"></td>';
cols += '<td><input type="checkbox" class="form-check-input" name="attendance_info' + counter + '"></td>';
cols += '<td><input type="checkbox" class="form-check-input" name="feedbackInfo' + counter + '"></td>';
cols += '<td>';
cols += '<input type="submit" class="btn btn-sm btn-success" value="Add"> ';
cols += '<input type="button" class="ibtnDel btn btn-sm btn-danger" value="X">';
cols += '</td>';
newRow.append(cols);
$("table.studentList").append(newRow);
counter++;
});
$("table.studentList").on("click", ".ibtnDel", function (event) {
$(this).closest("tr").remove();
counter -= 1
});
我的html文件如下所示:
<tr>
<form id="scheudleTable1"></form>
<td><input type="text" class="form-control" placeholder="Name" name="student_name0"></td><td><input type="checkbox" class="form-check-input" name="attendance_info0"></td>
<td><input type="checkbox" class="form-check-input" name="feedbackInfo0"></td>
<td><input type="submit" class="btn btn-sm btn-success" value="Add">
<input type="button" class="ibtnDel btn btn-sm btn-danger" value="X"></td></tr>
请帮助获得如下结果:
<tr>
<form id="myTable">
<td><input type="text" class="form-control" placeholder="Name" name="student_name0"></td><td><input type="checkbox" class="form-check-input" name="attendance_info0"></td>
<td><input type="checkbox" class="form-check-input" name="feedbackInfo0"></td>
<td><input type="submit" class="btn btn-sm btn-success" value="Add">
<input type="button" class="ibtnDel btn btn-sm btn-danger" value="X"></td></form></tr>
答案 0 :(得分:0)
创建一个表<table id="tableData">
之后,将所有<td>
写入单行,如下所示
var cols= '<td><input type="text" class="form-control" placeholder="Name" name="student_name' + counter + '"></td><td><input type="checkbox" class="form-check-input" name="attendance_info' + counter + '"></td>';
之后使用
将其附加到表ID$('#tableData').append(cols);
希望它有所帮助!!
答案 1 :(得分:0)
你可以试试这个:
https://jsfiddle.net/shashikantk1992/Lysu9nob/4/
//adding new row for table in upcoming classes module.
var counter = 0;
var scheudleTable1='mytable';
$("#addrow").on("click", function () {
//alert('asd');
var newRow = $("<form id='"+scheudleTable1+"'><tr>");
var cols = "";
cols += '<td><input type="text" class="form-control" placeholder="Name" name="student_name' + counter + '"/></td>';
cols += '<td><input type="checkbox" class="form-check-input" name="attendance_info' + counter + '"/></td>';
cols += '<td><input type="checkbox" class="form-check-input" name="feedbackInfo' + counter + '"/></td>';
cols += '<td>';
cols += '<input type="submit" class="btn btn-sm btn-success" value="Add"> ';
cols += '<input type="button" class="ibtnDel btn btn-sm btn-danger" value="X"/>';
cols += '</td>';
newRow.append(cols);
$("table.studentList").append(newRow);
counter++;
});
$("table.studentList").on("click", ".ibtnDel", function (event) {
$(this).closest("form").remove();
counter -= 1
});