如何插入数据库jquery多输入？

Question

我有两个jquery动态输入。我如何插入数据库所有项目。像这样;

fatura  |   urun
  1         apple
  2         banana

这里是Html代码;

<form action="post.php" id="form" method="post">
    <input name="fatura[]" type="text" />
    <input name="urun[]" type="text" " />
  </div>
</div>
<button class="btn btn-primary input-ekle">Add Item</button>
<input type="submit" value="Send">
</form>

这里是post.php; （这个代码只添加“fatura []”输入行。我想插入urun输入。）

$sql = "INSERT INTO siparis (fatura_id) VALUES (:fi)";
$ekle = $db->prepare($sql);
$ekle->bindParam(':fi', $row);
foreach ($_POST['fatura'] as $row) {
$ekle->execute();
}
if ($ekle) {
echo "ok";
} else {
echo "bad";
}

Answer 1

假设有多少＆＃34; fatura＆＃34; as＆＃34; urun＆＃34;，您可以尝试这样的事情：

$sql = "INSERT INTO siparis (fatura_id, urun_ismi) VALUES (:fi, :ui)" ;
$ekle = $db->prepare($sql) ;
$num = count($_POST['fatura']) ;
for ($i = 0 ; $i < $num ; $i++) {
    $ekle->bindParam(':fi', $_POST['fatura'][$i]) ;
    $ekle->bindParam(':ui', $_POST['urun'][$i]) ;
    $ekle->execute();
}