Question

好的，我们假设我们有一个带有这样的数组的变量

int[] digit;
int x = 5; 
for(int i=0;i < = 5; i++)
{ digit[i] = 0;}

var数字上的所有值数组都有0.所以我想要做的是我想使用增加增量的按钮控件来增加该数字的值（这意味着数字[4]到数字[3]等等，当数值在数字[4]中达到某个数字示例5时，它将返回到值0并且下一个var数字递增（数字[3]）。并且再次开始增加等等。

我已经尝试使用if并切换到这样发生

private btnClick_Click(Object Sender, Event Args)
{
     digit[4] +=1;
     if(digit[4] > 5) { digit[3] += 1;}
     if(digit[3] > 5) { digit[2] += 1;}
     //and so on
     switch(digit[4])
     {
         case 5: digit[4]=0;
     }
     //and so on
}

但它仅用于逻辑如果我们知道数组编号位置。如果我在15位数之类的地方检索该号码。如果我们在命令按钮上设置的数组很少，它就无法正确填充数组？

Imma已经混淆了这个想法，任何建议，帮助，讨论都不理解它。感谢。

Answer 1

如果您只想增加一个，而不是减去任何减法或增量，我想使用这样一个简单的解决方案：

private void btnClick_Click(Object Sender, Event Args) {
    int maxValue = 5;
    int carry = 1; // This is our increment

    // iterate through your digits back to front
    for(int i = digit.Length - 1; i >= 0; i--) {
        digit[i] += carry;  // increase the value by the carry. This will at least increment the last digit by one
        carry = 0;

        // if we reach our max value, we set the carry to one to add it to the next digit, and reset our current digit to 0.
        // If you wanted to increase by more than 1 a time, we would have to add some more calculations here as it would
        // be incorrect to just reset digit[i] to 0.
        if(digit[i] >= maxValue) {
            carry = 1; // the next digit will now be told to increase by one - and so forth
            digit[i] = 0;
        } else {
            break; // This will break out of the for - loop and stop processing digits as everything just fit nicely and we don't have to update more previous digits
        }
    }
}

一旦你达到44444并递增，你就会得到00000。

C＃增加的数组编号

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