Question

def menu():
print('Choose number to continue: ')
print('1 to create file')
print('2 to read file')
print('3 to append to file')
print('4 to calculate')
print('5 to quit')

def choice():
    choice=int(input('Enter menu choice: '))
    return choice


def option1():
    filename=input('Enter file name: ')
    file=open(filename,'w')
    print('Enter integers to be written to file and press enter when done.')
    count=1
    fox=1
    while count>=1:
        filedata=str(input('Enter integer '+str(fox)+' : '))
        count+=1
        fox+=1
        file.write(filedata)
        if filedata=='':
            file.close()
            menu
            break

def option2():
    try:
        open(file,'r')
        for line in file.readlines():
            print(line)
            file.close()
            menu()
    except:
        print('Error. You must first create a file in order to read it.')


def option3():
    try:
        open(file,'a')
        print('Enter integers to be appended to file and press enter when done.')
        count=1
        while count>=1:
         appenddata=int(input('Enter integer to append: '))
        count+=1
        file.write(appenddata)
        if appendata=='':
            file.close()
            menu

    except:
        print('Error. You must first create a file in order to read it.')



def option4():
    file= open('file', 'r')
    s = file.readlines()
    p = str(s)



    for line in s:
        printnum = 0

        total=0
        printnum += int(line)
        total += printnum


        print("The sum is: ", total)
        menu()


def option5():
    quit

def main():
    menu()
    t=choice()

    if t==1:
       option1()
       menu() 
    elif t==2:
        option2()
        menu
    elif t==3:
        option3()
        menu()
    elif t==4:
        option4()
        menu()
    else:
        option5()
main()

对于冗长的代码感到抱歉，这是我正在制作的菜单驱动的python程序。它允许用户选择第一个选项，然后打印菜单然后结束，而我希望它再次输入菜单选项。我可以看到为什么它正在这样做，但我想不出一种让他们选择第二/第三/第四选项的方法。感谢。

Answer 1

尝试使用循环重复菜单。

def main():

    menu()
    t=choice()
    while t != 5:    
        if t==1:
            option1()
        elif t==2:
            option2()
        elif t==3:
            option3()
        elif t==4:
            option4()
        else:
            print('Invalid Choice')

        print('')
        menu()
        t=choice()

# main
main()

文件python菜单在第一个选项后返回菜单

1 个答案: