Question

我有一个给定任务的先决条件列表。该列表包含构成逻辑表达式的其他任务（使用字母作为占位符）。示例如下所示：

prereqList = [["A", "|", "B"], "&", [["C", "&", "D"], "|", "E"], "&", "F"]

我还有一份已完成任务的清单：

completedTasks = ["A", "C", "F"]

我正在尝试在遵循条件逻辑的同时从prereqList中删除已完成的任务。对于上述示例，我希望输出为：

filtered_list = ["D", "|", "E"]

到目前为止我所拥有的：

def filter_prereqs(prereqList, completedTasks):
    ops = {
            "&": (lambda a, b: a in completedTasks and b in completedTasks),
            "|": (lambda a, b: a in completedTasks or b in completedTasks)
        }
        for i in range(prereqList):
            if isinstance(prereqList[i], list):
                filter_prereqs(prereqList[i], completedTasks)
            else:
                if prereqList[i] not in ops.keys():
                    pass
                else:
                    conditionMet = ops[prereqList[i]](prereqList[i-1],prereqList[i+1])
                    if conditionMet:

一直试图解决这个问题。任何帮助将不胜感激！

Answer 1

部分解决方案：

这是有效的，但仅适用于保守括号内的表达式＆＃34;。换句话说，它可以解析[["A", "&", "B"], "&", "C"]，但不能解析["A", "&", "B", "&", "C"]。因此，我无法解析您问题中的确切表达式，但我可以解析具有额外一对括号的逻辑等效版本。

#sentinel value that gets returned for an expression that's 100% completed
complete = object()

def remove_completed(expression, completed):
    if isinstance(expression, str):
        if expression in completed:
            return complete
        else:
            return expression
    left, operator, right = expression
    left = remove_completed(left, completed)
    right = remove_completed(right, completed)
    if operator == "|":
        if left is complete or right is complete:
            return complete
        else:
            return [left, "|", right]
    elif operator == "&":
        if left is complete:
            return right
        elif right is complete:
            return left
        else:
            return [left, "&", right]

prereqList = [[["A", "|", "B"], "&", [["C", "&", "D"], "|", "E"]], "&", "F"]
result = remove_completed(prereqList, ["A", "C", "F"])
print(result)

结果：

['D', '|', 'E']

如何过滤掉嵌套列表中的条件逻辑元素

1 个答案: